ClO4 is polar.
Yes, sodium perchlorate (NaClO4) can exist in the aqueous state when dissolved in water. In this state, it will dissociate into sodium ions (Na+) and perchlorate ions (ClO4-), which are surrounded by water molecules.
3 moles of (ClO4)3- and 1 mol AlAluminium perchlorate is Al)CLO4)3.10H2O.
By charge, I assume you mean oxidation number. Oxygen's oxidation number is a very dependable -2, with only a few strange exceptions. A better question would be "What is chlorine's oxidation number in ClO4-?" The answer would be +7.
The compound Ca(CLO4)2 is called calcium perchlorate. It consists of calcium ions (Ca²⁺) and perchlorate ions (ClO4⁻). In this formula, there are two perchlorate ions for each calcium ion, reflecting the need for charge balance in the compound.
The oxidation state of Mn in Mn(ClO4)3 is +7. This is because the overall charge of the perchlorate ion (ClO4)- is -1, and there are 3 perchlorate ions in Mn(ClO4)3, resulting in a total charge of -3. To balance this, the Mn ion must have an oxidation state of +7.
ClO2- shows a disproportionation reaction because in this species, the oxidation state of chlorine is in between -1 (in Cl-) and +4 (in ClO4-), which allows for both oxidation and reduction to occur in the same compound. ClO4- does not undergo disproportionation as the oxidation state of chlorine is already at its highest state, +7, making further oxidation not possible.
O.S of Mn = 3+ O.S. of Cl = 7+ O.S. of O = 2-
Perchlorate ion (ClO4-) is colorless.
Cu(ClO4)2 dissociates into Cu2+ ions and 2 ClO4- ions in solution. This results in the breakdown of the copper perchlorate compound into its constituent ions when dissolved in water. The balanced equation for the dissociation of Cu(ClO4)2 is: Cu(ClO4)2 -> Cu2+ + 2 ClO4-.
The formula for magnesium perchlorate is Mg(ClO4)2.
The chemical symbol for perchlorate is ClO4-.
The oxidation number of Mn in Mn(ClO4)3 is +7. Each Cl has an oxidation state of -1 and each O has an oxidation state of -2. The sum of the oxidation numbers should equal the charge of the molecule, which is 0 in this case.
The formula for the perchlorate ion is ClO4-. It consists of one chlorine atom bonded to four oxygen atoms.
ClO4 is polar.
In ClO4-, the oxidation number of Cl is +7, and the oxidation number of each O is -2.
The symbol for the oxyanion perchlorate ion is ClO4-.