The result of crossing two individuals who are heterozygous for two different traits (LlGg x LlGg) would typically follow a 9:3:3:1 phenotypic ratio for a dihybrid cross. This means you would expect to see a mix of four different phenotypes in the offspring, with a 9:3:3:1 ratio between those phenotypes.
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
It depends what the second gene for each parent is. Bx+ and Ax+ is the information given. The x could be B for Bx and A for Ax. The x could also be O for both. So AA and BB or AO and BO. In all cases the cross between AA and BB would produce AB. For the cross between AO and BO, the result would be AB, BO, AO, and OO in a 1:1:1:1 ratio. If the cross is AA and BO, the result would be AB and AO in a 1:1 ratio. If the cross is BB and AO the result would be AB and BO in a 1:1 ratio. In all cases the Rh factor would be +
A punnett square is the diagram used to determine the expected genotypic ratios for the offspring.A dihybrid cross is a cross involving two different traits. For example RrDd X RrDd would be a dihybrid cross. You could use a punnett square to determine the expected ratios for this cross:RDRdrDrdRDRRDDRRDdRrDDRrDdRdRRDdRRddRrDdRrddrDRrDDRrDdrrDDrrDdrdRrDdRrddrrDdrrddOne parent's genotype is shown across the top, the other down the side (both in bold).
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
The cross RR X Dd is showing two different genes for the parents (it is showing RR for one parent and Dd for the other) - therefore this is not a dihybrid cross. However, if it was RRDd X RRDd, this would be a dihybrid cross. For a dihybrid cross, you need to include two different genes (and show these genes in both the parents). So - BbFf X bbff, GGTT X ggtt, KKPp X KkPp - are all examples of dihybrid crosses.
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
A lipizaner x Arabian.
Rr x Rr is an example of a monohybrid cross, specifically a cross between two heterozygous individuals for a single trait. This type of cross helps determine the possible genotypic and phenotypic outcomes for the offspring.
It depends what the second gene for each parent is. Bx+ and Ax+ is the information given. The x could be B for Bx and A for Ax. The x could also be O for both. So AA and BB or AO and BO. In all cases the cross between AA and BB would produce AB. For the cross between AO and BO, the result would be AB, BO, AO, and OO in a 1:1:1:1 ratio. If the cross is AA and BO, the result would be AB and AO in a 1:1 ratio. If the cross is BB and AO the result would be AB and BO in a 1:1 ratio. In all cases the Rh factor would be +
The y-intercept is where the line crosses the y-axis, and the x-intercept is where the line cross the x-axis
The duration of X-Cross is 1.5 hours.
The cross would result In 50% pink and 50% white.
X-Cross was created on 2007-12-01.
If x is the angle between the two vectors then the magnitudes are equal if cos(x) = sin(x). That is, when x = pi/4 radians.
x is a-cross
y=1 does not cross the x-axis. It is a line parallel to the x-axis (and therefore can't ever cross it)
Force = Mass x Acceleration Stress = Force / Cross Sectional Area