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How do you set this up Two heterodox red flowers (white flowers are recessive) are crossed.?
When crossing two heterozygous red flowers (Rr), you would use a Punnett square to determine the possible genotypes and phenotypes of the offspring. In this case, the genotypes of the parents are Rr x Rr. The possible offspring genotypes would be RR, Rr, and rr, with a phenotypic ratio of 1 red : 2 pink : 1 white flower.
What are the possible gametes types that can be produced from a parent who is YrRr?
Make two punnett squares- one for Yy x YY and one for rr x RR the possible outcomes for Yy x YY are: YY Yy the only outcome for rr x RR is Rr. so the gametes of the two could be either YY Rr or Yy Rr
What is individuals having two of the same alleles of a gene?
A monohybrid cross is a cross between two individuals that are homozygous for different alleles of the same gene. An example is a cross between a red-eyed (RR) fruit fly and a white-eyed (WW) fruitfly.
In a BB x bb cross?
In a BB x bb cross, all offspring will have the genotype Bb. The offspring will exhibit the dominant trait of the B allele.
What kinds of offsprings can be produced if 2 pink flowered plants are crossed?
In general, pink flowers tend to be an example of incomplete dominance of the gene for red flowers. Therefore, the phenotypic ratio of a cross between two pink flowers would be the same as the genotypic ratio of 1:2:1. In other words, 1 red to 2 pink to 1 white.
What is the probability of Rr x Rr producing wrinkled seeds?
In a cross between two heterozygous pea plants (Rr x Rr), where "R" represents the dominant allele for smooth seeds and "r" represents the recessive allele for wrinkled seeds, the probability of producing wrinkled seeds (rr) can be determined using a Punnett square. The genotype ratio from this cross is 1 RR : 2 Rr : 1 rr. Therefore, the probability of producing wrinkled seeds (rr) is 1 out of 4, or 25%.
What is RR x Rr?
The genetic cross of RR (homozygous dominant) and Rr (heterozygous) can be represented using a Punnett square. The possible offspring genotypes from this cross are RR and Rr. Specifically, there is a 50% chance for the RR genotype and a 50% chance for the Rr genotype. Therefore, all offspring will exhibit the dominant trait, with half being homozygous dominant and half being heterozygous.
If you were to cross pink flowering four o'clocks with white flowering four o' clocks what results would you expect Provide a punnett square to support your answer?
The cross would result In 50% pink and 50% white.
Is RR X Dd a dihybrid cross?
The cross RR X Dd is showing two different genes for the parents (it is showing RR for one parent and Dd for the other) - therefore this is not a dihybrid cross. However, if it was RRDd X RRDd, this would be a dihybrid cross. For a dihybrid cross, you need to include two different genes (and show these genes in both the parents). So - BbFf X bbff, GGTT X ggtt, KKPp X KkPp - are all examples of dihybrid crosses.
A pea plant with round seeds has the genotype Rr you cross this plant with a wrinkled seed plant genotype rr what is the probability that the offspring will have wrinkled seeds?
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
What is the ratio of red roan white offspring from the cross of a roan bull with a white cow?
Lets start with using letters to symbolize each allele of each parent: Roan Bull x White Cow --> Rr x rr (where the alleles R = red and r = white). The resulting ratio of offspring is the following: Rr = 50% rr = 50% RR = 0% Since there are too many little "r"'s and not enough big "R"'s, we can only get a cross of white and roan calves to a ratio of 1:1. Red calves do not exist in this cross.
In a certain plant red flowers are dominant to white flowers. If the cross of two red flowered plants produces some red flowered plants and some white flowered plants what is the genotype of the par?
In this case, since red flowers are dominant to white flowers and the cross of two red-flowered plants produces both red and white flowered offspring, the genotype of the parents must be heterozygous (Rr) for red flowers. This means both parents carry one allele for red flowers (R) and one for white flowers (r). The offspring ratio suggests that the cross is between Rr x Rr, resulting in a genotypic ratio of 1 RR : 2 Rr : 1 rr, with the rr genotype producing the white flowers.
In pea plants inflated pods are dominant to constricted pods what crosses is a test cross?
A test cross would involve crossing a pea plant with a constricted pod (to determine its genotype) with a homozygous recessive plant (constricted pod), as this cross would reveal whether the first plant is heterozygous or homozygous dominant for the trait of pod shape.
Punnett square to predict offspring blood type?
Let's say we're talking about red flowers (red=dominant, R allele) vs white flowers (white=recessive, r allele) If you cross two homozygous red flowers, RR x RR, you can only get RR offspring, or all red flowers. RR=genotype (what alleles, or genes, they have), red=phenotype (what they look like) To make the Punnett square, draw a 4-box diagram on a piece of paper by drawing a diagonal line and then a horizontal line halfway down so you get 4 squares. On the top of the box, put R R and along the left side, put R and then another R under it. To fill in the boxes for the Punnett square, cross the top left-hand gene (R) with the top gene on the left-hand side. You'll get RR. Do the same for the top right-hand gene (R) and the top gene on the side. You'll also get RR. Cross the bottom R with the left gene on the top (R) and the right gene on the top. All combinations will be RR in this example. If you had a red flower that had a homozygous genotype (RR) with a white flower, also homozygous (rr), the results are more interesting. When you draw your Punnett square, you'll see that you get one RR combination, two Rr combinations and one rr combination. This means that the F1 generation (offspring) will be: 25% homozygous red (RR) 50% heterozygous red (Rr) 25% homozygous white (rr) Put another way, you'll have one white flower and three red flowers, and two of those red flowers carry a gene for white which is not expressed because it is recessive.
What is the probability Two individuals with autosomal recessive trait will have a child with the same trait?
If they are expressing the trait, 100%, as their genotypes would be, rr X rr If they both carry the trait and it is dominated, Rr X Rr, then the probability would be, 25% of their child expressing the trait.
How do you set this up Two heterodox red flowers (white flowers are recessive) are crossed.?
When crossing two heterozygous red flowers (Rr), you would use a Punnett square to determine the possible genotypes and phenotypes of the offspring. In this case, the genotypes of the parents are Rr x Rr. The possible offspring genotypes would be RR, Rr, and rr, with a phenotypic ratio of 1 red : 2 pink : 1 white flower.
What are the possible genotypes if you do a punnett square with one parent who is Homozygous dominant RR for being resistant to poison ivy and one parent who is allergic to poison ivy rr?
RR X rr 100% Rr Heterozygous resistant for poison ivy.
