The stoichiometric volume ratio for complete combination is approximately 2:1 (it's not PRECISELY 2:1 because neither hydrogen nor oxygen is an ideal gas), so if you want them to combine as completely as possible, 2/3 of that 250 ml should be hydrogen and 1/3 should be oxygen.
You'd do better measuring masses (in which case you want the ratio to be 2.016 parts hydrogen to 15.9994 parts oxygen), but that's a lot harder to do, and going by volume is definitely close enough to give one heck of a bang when you set it off. I saw this done once, using an ordinary party balloon and a candle on the end of a very long stick in a large auditorium, and it literally shook the entire building when it went off.
Approximately twice as much volume of hydrogen as of oxygen: Both gases are diatomic and nearly ideal at normal temperature and pressure, and the atomic ratio of hydrogen to oxygen in water is 2.
In the Hoffman apparatus demonstration, the ratio of hydrogen and oxygen produced indicates the ratio of water's components (H2O). Since water molecule consists of two hydrogen atoms and one oxygen atom, the volume of hydrogen gas produced will be twice that of the oxygen gas when water is electrolyzed.
When an electric current is passed through water, water is split into it's two component gasses- hydrogen and oxygen. You will get about twice as much hydrogen as oxygen- since water (H2O) has twice the hydrogen as oxygen.
A gram of hydrogen has a greater volume than a gram of oxygen at the same temperature and pressure, as hydrogen has a lower molecular weight and therefore occupies more space per gram compared to oxygen.
the chemical formula of water is H2O, so 2 hydrogen atoms and 1 oxygen atoms. if you have 1 mole of oxygen atoms (O2) and 2 mole of hydrogen atoms (H2) in a test tube then you will form 2 mole of water. uses avagadros number and the mole formula to find out how much of each substance you will form.
Approximately twice as much volume of hydrogen as of oxygen: Both gases are diatomic and nearly ideal at normal temperature and pressure, and the atomic ratio of hydrogen to oxygen in water is 2.
The volume of hydrogen should be twice the volume of oxygen formed in the electrolysis of water because the ratio of the number of moles of hydrogen to oxygen in water is 2:1. This is based on the molecular formula of water, H2O, where each water molecule contains two hydrogen atoms and one oxygen atom.
Don't try it because if you have 1 volume of oxygen to 2 volumes of hydrogen, it is explosive!
In the Hoffman apparatus demonstration, the ratio of hydrogen and oxygen produced indicates the ratio of water's components (H2O). Since water molecule consists of two hydrogen atoms and one oxygen atom, the volume of hydrogen gas produced will be twice that of the oxygen gas when water is electrolyzed.
1 mole of water is equal to 18 g.2 g hydrogen is equal to 22,25 L.16 g oxygen is equal to 11,2 L.The volumes ratio H/O is approx. 2.
When an electric current is passed through water, water is split into it's two component gasses- hydrogen and oxygen. You will get about twice as much hydrogen as oxygen- since water (H2O) has twice the hydrogen as oxygen.
A gram of hydrogen has a greater volume than a gram of oxygen at the same temperature and pressure, as hydrogen has a lower molecular weight and therefore occupies more space per gram compared to oxygen.
the chemical formula of water is H2O, so 2 hydrogen atoms and 1 oxygen atoms. if you have 1 mole of oxygen atoms (O2) and 2 mole of hydrogen atoms (H2) in a test tube then you will form 2 mole of water. uses avagadros number and the mole formula to find out how much of each substance you will form.
The reaction is 2H2 + O2-> 2H2O So, both the molar and volume ratios would be 2 moles(liters) of hydrogen to every mole(liter) of oxygen. By weight, the ratio would be about 8 grams of oxygen to every gram of hydrogen
The reaction between hydrogen gas and oxygen gas forms water, with 2 moles of hydrogen gas reacting with 1 mole of oxygen gas. This means that twice as much hydrogen gas is required compared to oxygen gas for the reaction to occur completely.
To determine the volume of oxygen remaining after the reaction, we first need to determine the stoichiometry of the reaction. The balanced chemical equation for the reaction of hydrogen and oxygen is 2H2 + O2 -> 2H2O, meaning 2 volumes of hydrogen react with 1 volume of oxygen to produce 2 volumes of water vapor. Since the reaction ratio is 2:1 for hydrogen to oxygen, the 8cm3 of hydrogen will react with 4cm3 of oxygen. Therefore, the initial 20cm3 of oxygen minus the 4cm3 used in the reaction leaves 16cm3 of oxygen remaining.
During electrolysis of water, the volume of gas produced at the anode (oxygen) is twice that of the volume of gas produced at the cathode (hydrogen). This is because water molecules (H2O) split into two hydrogen atoms for every one oxygen atom when an electric current is passed through the water during electrolysis.