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V1= x says

V2 = 1000-x

M1=10mol/L

M2=3mol/L

M = 6mol/L

M = (M1V1+M2V2)/(V1+V2)

6={10*x+3(1000-x)}/(x+1000-x)

6000=7x+3000

x=428.57

V1= 428.57ml

V2= 1000-428.57

V2= 571.2ml

so,

the volume of 10M HCl =428.57ml

the volume of 3M HCl =571.2ml

IT IS DONE BY

JAGADEESH

SAI

VINOD

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Wiki User

15y ago
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15y ago

V1= x says

V2 = 1000-x

M1=10mol/L

M2=3mol/L

M = 6mol/L

M = (M1V1+M2V2)/(V1+V2)

6={10*x+3(1000-x)}/(x+1000-x)

6000=7x+3000

x=428.57

V1= 428.57ml

V2= 1000-428.57

V2= 571.2ml

so,

the volume of 10M HCl =428.57ml

the volume of 3M HCl =571.2ml

IT IS DONE BY

JAGADEESH

SAI

VINOD

This answer is:
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Wiki User

11y ago

use your titration equations

V1M1=V2M2

0.319L * 6.80 = x * 6.00

2.17 = 6x

2.17/6 = x

0.362L = x or 362ml

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6y ago

V1M1 = V2M2(x ml)(7.00 M) = (291 ml)(6.80 M)

x = 283 ml

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6y ago

The volume is 282 mL.

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Q: What volume of 6.00M HCl can be made from 319 mL of 6.80M HCl?
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