0
What else can I help you with?
If both parents are heterozygous for polydactyly what percentage of offspring will exhibit polydactyly?
There is a 25% chance that the offspring will exhibit polydactyly if both parents are heterozygous for the trait.
What is the probability that the children will be heterozygous?
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
How do two heterozygous organisms produce on offspring with a recessive phenotype?
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
The offspring of two parents that are heterozygous for a given trait have a percent chance of being homozygous for that trait?
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.
What are the phenotypes possible for a hybrid tall parents?
When considering hybrid tall parents, the phenotypes of their offspring can vary depending on the genetic makeup of the parents. If both parents are homozygous tall (TT), all offspring will be tall (TT). If one parent is homozygous tall (TT) and the other is heterozygous tall (Tt), all offspring will also be tall (TT or Tt). However, if both parents are heterozygous (Tt), the offspring can exhibit three possible phenotypes: tall (TT or Tt) and short (tt), following a typical Mendelian ratio of 3 tall to 1 short.
What was the probability that two heterozygous parents would have an offspring that produced rounds seeds?
3:4 or 75%
What is probability that two heterozygous parents would have an offspring that produced round seeds?
It is a 75% chance that the seeds will be round.
What is probability that wto heterozygous parents would have an offspring that produced round seeds?
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
What is the probability that two heterozygous parents would have an offspring that produced round seeds from Mendel?
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
If both parents are heterozygous for polydactyly what percentage of offspring will exhibit polydactyly?
There is a 25% chance that the offspring will exhibit polydactyly if both parents are heterozygous for the trait.
What is the probability that the offspring will have wrink seeds?
To determine the probability of offspring having wrinkled seeds, we need to know the genetic makeup of the parents. If we assume that wrinkled seeds are a recessive trait (represented by "r") and smooth seeds are dominant (represented by "R"), then the probability depends on the genotypes of the parents. For example, if both parents are heterozygous (Rr), there is a 25% chance that the offspring will inherit the wrinkled seed trait (rr). Without specific parental genotypes, we cannot provide an exact probability.
What is the probability that an offspring mouse will be born with the genotype ff ee?
To determine the probability of an offspring mouse being born with the genotype ff ee, you need to know the genotypes of the parent mice. If both parents are heterozygous (Ff Ee), the probability of producing ff offspring is 1/4 and for ee offspring is also 1/4. To find the probability of the combined genotype ff ee, you multiply these probabilities: (1/4) x (1/4) = 1/16. Thus, there is a 1/16 probability that an offspring mouse will have the genotype ff ee, assuming both parents are Ff Ee.
What is the possibility that two heterozygous parents would have an offspring that produced round seeds?
In pea plants, the round seed trait (R) is dominant over the wrinkled seed trait (r). If both parents are heterozygous (Rr), the possible offspring genotypes are RR, Rr, and rr, with a 75% chance of producing round seeds (RR or Rr) and a 25% chance of producing wrinkled seeds (rr). Therefore, there is a 75% possibility that two heterozygous parents would have an offspring that produces round seeds.
If purple flower color is dominant over white flower color how can two purple flowered parents produce while flowered offspring?
It can happen when both parents are a heterozygous
Used to determine the probability of having specific offspring from two known parents?
Genotype is used to determine the probability of having specific offspring from two known parents.
What is the probability that the genotype AAA will be produced by the parents AAA x AAA?
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%
