A horse. nuff said
A mole of S (32 g) weighs more than a mole of Sodium Na (23 g)
Sucrose is more soluble in hot water due to the increase in molecular motion of the solute and solvent.
You've got it in reverse. When sucrose dissolves in water, sucrose is the solute, and water is the solvent. In order to dissolve, sucrose molecules have to be more attracted to water molecules than they are to other sucrose molecules. If the attraction of sucrose to sucrose was greater than the attraction of sucrose to water, then there would be no reason for the solid sucrose to turn into the aqueous sucrose solution. Sucrose molecules would simply remain firmly attached to each other if that were the case.
You've got it in reverse. When sucrose dissolves in water, sucrose is the solute, and water is the solvent. In order to dissolve, sucrose molecules have to be more attracted to water molecules than they are to other sucrose molecules. If the attraction of sucrose to sucrose was greater than the attraction of sucrose to water, then there would be no reason for the solid sucrose to turn into the aqueous sucrose solution. Sucrose molecules would simply remain firmly attached to each other if that were the case.
This is because the potato, which is mostly water, is in a hypertonic solution (a solution with less water and more solute --here, sucrose-- than the potato). Since the solutions want to reach equilibrium (equal amounts of sucrose and water in both the solution and the potato), water diffuses out of the potato and sucrose diffuses into it. The potato loses its water weight, and sucrose doesn't replace the weight lost, the potato weighs less.
One atom of sodium weighs more than one atom of oxygen. Thus, one mole of sodium weighs more than one mole of oxygen.
A mole of S (32 g) weighs more than a mole of Sodium Na (23 g)
Sucrose is more soluble in hot water due to the increase in molecular motion of the solute and solvent.
A mole of potassium. Sodium weighs 22.990 g/mol while potassium weighs 39.068 g/mol.
It would be a mole of water because you find the molar mass of each compound, finding water is 18.016 g/mol and methane is 16.042 g/mol. Why? water= H2O H 2 x 1.008 O 1 x 16.000 18.016 g/mol methane= CH4 C 1 x 12.010 H 4 x 1.008 16.042 g/mol
You've got it in reverse. When sucrose dissolves in water, sucrose is the solute, and water is the solvent. In order to dissolve, sucrose molecules have to be more attracted to water molecules than they are to other sucrose molecules. If the attraction of sucrose to sucrose was greater than the attraction of sucrose to water, then there would be no reason for the solid sucrose to turn into the aqueous sucrose solution. Sucrose molecules would simply remain firmly attached to each other if that were the case.
You've got it in reverse. When sucrose dissolves in water, sucrose is the solute, and water is the solvent. In order to dissolve, sucrose molecules have to be more attracted to water molecules than they are to other sucrose molecules. If the attraction of sucrose to sucrose was greater than the attraction of sucrose to water, then there would be no reason for the solid sucrose to turn into the aqueous sucrose solution. Sucrose molecules would simply remain firmly attached to each other if that were the case.
Sucrose is more soluble in hot water due to the increase in molecular motion of the solute and solvent.
This is because the potato, which is mostly water, is in a hypertonic solution (a solution with less water and more solute --here, sucrose-- than the potato). Since the solutions want to reach equilibrium (equal amounts of sucrose and water in both the solution and the potato), water diffuses out of the potato and sucrose diffuses into it. The potato loses its water weight, and sucrose doesn't replace the weight lost, the potato weighs less.
These chemicals react in a direct proportion of one to one, measured in moles of course, not by weight. A mole of NaOH weighs more than a mole of HCl.
Adding one mole of salt raises the boiling point of the water more than adding one mole of sugar to the water
As water temperature increases, the energy of water particles also increases, allowing them to interact more readily with sucrose molecules and increase its solubility. This increased energy helps break down the intermolecular forces holding sucrose together, allowing it to dissolve more easily in the water.