PV/T=Constant
Providing the volume remains constant.
P/T=C
35/313=20/T
Therefore T=178.9Kelvin
To calculate the molar heat of vaporization, we can use the Clausius-Clapeyron equation: ΔHvap = -R * T * ln(P2/P1) Where: ΔHvap = molar heat of vaporization R = gas constant (8.314 J/mol*K) T = temperature difference in Kelvin (40°C + 273 - 0°C = 313 K) P1 = vapor pressure at lower temperature (134 mmHg) P2 = vapor pressure at higher temperature (760 mmHg, since boiling point is at atmospheric pressure) Plugging in the values, we have: ΔHvap = -8.314 * 313 * ln(760/134) = -8.314 * 313 * ln(5.67) ≈ -37.4 kJ/mol Therefore, the molar heat of vaporization of dichloromethane is approximately 37.4 kJ/mol.
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The specific heat can be calculated using the formula: ( q = mc\Delta T ), where ( q ) is the heat absorbed, ( m ) is the mass, ( c ) is the specific heat, and ( \Delta T ) is the temperature change. Plugging in the values: ( 67.2 = (44.0) \times c \times 11 ), solving for ( c ) gives a specific heat of approximately 0.138 J/g∙K.
The boiling point of carbon dioxide is -57 °C (or 216.6 K, or -70 °F), but this will only take place at pressures in excess of 5.1 atmospheres. It turns out that CO2 doesn't like to hang around in liquid form unless it is under a good deal of pressure. It will sublime (change directly from a gas into a solid) at anything above −78 °C, and deposit directly as a solid from the gas at anything below −78 °C. In environments without elevated pressure, it changes state from solid to gas and gas to solid (depending on temperature) directly without going through a liquid phase.Added:At 1.0 bar, normal pressure, it sublimes (solid-gas phase change) at -78 °C, 194.7 K without passing through its liquid phase.At 5.185 bar the boiling point (from liquid) is -57 °C, 216.6 K.
The first letter shows when the object in space was discovered. The "U" shows the period October 16-31. The second letter shows what order the object was found in the amount of time the first letter represented. A= first, B= 2, C= third, and so on. Basically, Eris (Planet 2003 UB313) was found between October 16-21, and was the second object discovered in that period of time. (See http://www.nasa.gov/audience/forstudents/5-8/features/F_Tenth_Planet.html for more info)
313 Kelvin.
To calculate the molar heat of vaporization, we can use the Clausius-Clapeyron equation: ΔHvap = -R * T * ln(P2/P1) Where: ΔHvap = molar heat of vaporization R = gas constant (8.314 J/mol*K) T = temperature difference in Kelvin (40°C + 273 - 0°C = 313 K) P1 = vapor pressure at lower temperature (134 mmHg) P2 = vapor pressure at higher temperature (760 mmHg, since boiling point is at atmospheric pressure) Plugging in the values, we have: ΔHvap = -8.314 * 313 * ln(760/134) = -8.314 * 313 * ln(5.67) ≈ -37.4 kJ/mol Therefore, the molar heat of vaporization of dichloromethane is approximately 37.4 kJ/mol.
If V1 = V2 => p1 / T1 = p2 / T2 <=> p2 = p1 * T2 / T1 Let's assume that T1 = 20 C Degree = 313 K => p2 = p1 * 343/313 => p2 = 1.10 p1 which means 10% higher pressure.
At normal pressure steam changes to liquid water at 212 degree F.
0oC is equal to 273K, and the magnitude of the individual degrees is the same, for the Celsius scale is used to define K. So 40oC is (40+273)K. = 313K. [And for the pedant, the triple point of water is 273.16K. But that makes no difference to the above.]
1 and 313 (313 is a prime number).
313 is a prime so radical 313 cannot be simplified.
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It is: 334 -313 = 21
x x 313 = (x)(313) = 313x
Moles Cl2 = 25g x 1mol/71g 0.35 molesPV =nRT and T = PV/nR T = (1.5)(6)/(0.35)(.0821) T = 313 deg K = 40.2 deg C to 3 sig figs
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