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In a galvanic cell involving magnesium (Mg) and zinc (Zn), the cathode is the electrode where reduction occurs. In this case, zinc acts as the cathode because it has a higher reduction potential compared to magnesium. Therefore, zinc ions in solution gain electrons and are reduced to solid zinc at the cathode, while magnesium oxidizes at the anode.

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What is the voltage of a galvanic cell with cu and mg 2.71?

The voltage of a galvanic cell can be calculated using the standard reduction potentials of the half-reactions involved. For a cell with copper (Cu) and magnesium (Mg), the standard reduction potential for Cu²⁺/Cu is +0.34 V, and for Mg²⁺/Mg, it is -2.37 V. The overall cell potential (E°cell) can be calculated as E°(cathode) - E°(anode), resulting in E°cell = 0.34 V - (-2.37 V) = 2.71 V. Therefore, the voltage of the galvanic cell with copper and magnesium is 2.71 V.


What is the standard cell notation of a galvanic cell made with msgnesium (Mg) and gold (Au)?

The standard cell notation for a galvanic cell made with magnesium (Mg) and gold (Au) can be represented as: Mg(s) | Mg²⁺(aq) || Au³⁺(aq) | Au(s). In this notation, magnesium is the anode (oxidation occurs) and gold is the cathode (reduction occurs), with the vertical bars separating different phases and the double vertical bar indicating the salt bridge.


What is the stranded cell notation of a galvanic cell made with magnesium (Mg) and gold (Au)?

The stranded cell notation for a galvanic cell made with magnesium (Mg) and gold (Au) is written as: [ \text{Mg(s)} | \text{Mg}^{2+}(aq) || \text{Au}^{3+}(aq) | \text{Au(s)} ] In this notation, the anode (Mg) is on the left side, while the cathode (Au) is on the right, with a double vertical line (||) representing the salt bridge that separates the two half-cells.


What is the voltage of a galvanic cell made with magnesium (Mg) and golf (Au)?

The voltage of a galvanic cell made with magnesium (Mg) as the anode and gold (Au) as the cathode can be estimated using standard reduction potentials. Magnesium has a standard reduction potential of -2.37 V, while gold has a standard reduction potential of +1.50 V. The overall cell potential can be calculated by subtracting the anode potential from the cathode potential, resulting in a voltage of approximately +3.87 V for the cell. This positive voltage indicates that the cell can generate electrical energy.


What is the voltage of galvanic cell made with magnesium (Mg) and gold (Au)?

4.2V

Related Questions

Which would be the anode in a magnesium and zinc galvanic cell?

Mg(s) Epi-Boii


What is the voltage of a galvanic cell with cu and mg 2.71?

The voltage of a galvanic cell can be calculated using the standard reduction potentials of the half-reactions involved. For a cell with copper (Cu) and magnesium (Mg), the standard reduction potential for Cu²⁺/Cu is +0.34 V, and for Mg²⁺/Mg, it is -2.37 V. The overall cell potential (E°cell) can be calculated as E°(cathode) - E°(anode), resulting in E°cell = 0.34 V - (-2.37 V) = 2.71 V. Therefore, the voltage of the galvanic cell with copper and magnesium is 2.71 V.


What is the standard cell notation of a galvanic cell made with msgnesium (Mg) and gold (Au)?

The standard cell notation for a galvanic cell made with magnesium (Mg) and gold (Au) can be represented as: Mg(s) | Mg²⁺(aq) || Au³⁺(aq) | Au(s). In this notation, magnesium is the anode (oxidation occurs) and gold is the cathode (reduction occurs), with the vertical bars separating different phases and the double vertical bar indicating the salt bridge.


What is the stranded cell notation of a galvanic cell made with magnesium (Mg) and gold (Au)?

The stranded cell notation for a galvanic cell made with magnesium (Mg) and gold (Au) is written as: [ \text{Mg(s)} | \text{Mg}^{2+}(aq) || \text{Au}^{3+}(aq) | \text{Au(s)} ] In this notation, the anode (Mg) is on the left side, while the cathode (Au) is on the right, with a double vertical line (||) representing the salt bridge that separates the two half-cells.


What is the voltage of a galvanic cell made with magnesium (Mg) and golf (Au)?

The voltage of a galvanic cell made with magnesium (Mg) as the anode and gold (Au) as the cathode can be estimated using standard reduction potentials. Magnesium has a standard reduction potential of -2.37 V, while gold has a standard reduction potential of +1.50 V. The overall cell potential can be calculated by subtracting the anode potential from the cathode potential, resulting in a voltage of approximately +3.87 V for the cell. This positive voltage indicates that the cell can generate electrical energy.


What is oxidized in a galvanic cell?

The anode


What is the voltage of galvanic cell made with magnesium (Mg) and gold (Au)?

4.2V


What is the standard cell notation of a galvanic cell made with mg and Au?

Mg(s) | Mg2+(aq)Au+(aq) | Au(s)


What is the standard cell notation of the galvanic cell made with mg and Au?

Mg(s) | Mg2+(aq)Au+(aq) | Au(s)


What is the standard cell notation of a galvanic cell made with magnesium (Mg) and (Au)?

Mg(s) | Mg2+(aq) Au+(aq) | Au(s)


What is the standard cell notation of a galvanic cell made with magnesium and gold?

Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)


What is the voltage of a galvanic cell made with magnesium (Mg) and gold (Au)?

4.2 V