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What would you need to do to calculate molality of 10g of NaCI in 2Kg of water?
To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
What would you need to do to calculate the molality of 10 mol of NACI in 200 mol water?
To calculate the molality of NaCl in a solution, you would need to divide the number of moles of solute (NaCl) by the mass of the solvent (water) in kilograms. Since you have 10 mol of NaCl and 200 mol of water, you first need to convert the moles of water to kilograms. Given that the molar mass of water is approximately 18 g/mol, 200 mol of water corresponds to 3600 g, or 3.6 kg. Finally, calculate the molality using the formula: molality (m) = moles of solute / kilograms of solvent, resulting in 10 mol / 3.6 kg.
What would you need to do to calculate the molality of 10g of NaCI in 2kg of water?
To calculate the molality of 10 g of NaCl in 2 kg of water, first, determine the number of moles of NaCl by using its molar mass (approximately 58.44 g/mol). Divide the mass of NaCl (10 g) by its molar mass to find the moles. Then, use the formula for molality (m) which is moles of solute per kilogram of solvent: m = moles of NaCl / mass of water in kg (2 kg). Finally, substitute the values to get the molality.
What would you need to do to calculate the molality of 10 g of NaCI in 2kg of water?
To calculate the molality of NaCl in water, first, you need to determine the number of moles of NaCl by using its molar mass (approximately 58.44 g/mol). For 10 g of NaCl, divide 10 g by 58.44 g/mol to find the moles. Then, use the mass of the solvent (water) in kilograms; since you have 2 kg of water, molality is calculated as the number of moles of solute divided by the mass of solvent in kilograms. The formula is: molality (m) = moles of solute / kg of solvent.
How do you calculate the molality of 10g of NaCI in 2kg of water?
To calculate the molality (m) of a solution, use the formula: [ \text{molality} (m) = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}. ] First, convert the mass of NaCl into moles by using its molar mass (approximately 58.44 g/mol). For 10 g of NaCl, you have: [ \text{moles of NaCl} = \frac{10 , \text{g}}{58.44 , \text{g/mol}} \approx 0.171 , \text{mol}. ] Then, divide the moles by the mass of the solvent (water) in kilograms: [ m = \frac{0.171 , \text{mol}}{2 , \text{kg}} \approx 0.0855 , \text{mol/kg}. ] So, the molality of the solution is approximately 0.0855 mol/kg.
What would you need to do to calculate molality of 10g of NaCI in 2Kg of water?
To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
What would you need to calculate the molality of 10 g of NaCI in 2 kg of water?
To calculate the molality of 10 g of NaCl in 2 kg of water, you need to determine the number of moles of NaCl and the mass of the solvent (water) in kilograms. First, calculate the molar mass of NaCl, which is approximately 58.44 g/mol. Then, divide the mass of NaCl (10 g) by its molar mass to find the number of moles, and finally, use the formula for molality: molality = moles of solute / mass of solvent (in kg). In this case, the calculation would be molality = (10 g / 58.44 g/mol) / 2 kg.
What would you need to do to calculate the molality of 10 mol of NACI in 200 mol water?
To calculate the molality of NaCl in a solution, you would need to divide the number of moles of solute (NaCl) by the mass of the solvent (water) in kilograms. Since you have 10 mol of NaCl and 200 mol of water, you first need to convert the moles of water to kilograms. Given that the molar mass of water is approximately 18 g/mol, 200 mol of water corresponds to 3600 g, or 3.6 kg. Finally, calculate the molality using the formula: molality (m) = moles of solute / kilograms of solvent, resulting in 10 mol / 3.6 kg.
What would you need to do to calculate the molality of 10g of NaCI in 2kg of water?
To calculate the molality of 10 g of NaCl in 2 kg of water, first, determine the number of moles of NaCl by using its molar mass (approximately 58.44 g/mol). Divide the mass of NaCl (10 g) by its molar mass to find the moles. Then, use the formula for molality (m) which is moles of solute per kilogram of solvent: m = moles of NaCl / mass of water in kg (2 kg). Finally, substitute the values to get the molality.
What would you need to do to calculate the molality of 10 g of NaCI in 2kg of water?
To calculate the molality of NaCl in water, first, you need to determine the number of moles of NaCl by using its molar mass (approximately 58.44 g/mol). For 10 g of NaCl, divide 10 g by 58.44 g/mol to find the moles. Then, use the mass of the solvent (water) in kilograms; since you have 2 kg of water, molality is calculated as the number of moles of solute divided by the mass of solvent in kilograms. The formula is: molality (m) = moles of solute / kg of solvent.
What would you need to do to calculate the molality of 0.2 kg of NaCI in 3 kg of?
To calculate the molality of 0.2 kg of NaCl in 3 kg of water, first determine the number of moles of NaCl by using its molar mass (approximately 58.44 g/mol). Convert 0.2 kg of NaCl to grams (200 g) and calculate the moles: ( \text{moles} = \frac{200 \text{ g}}{58.44 \text{ g/mol}} ). Finally, use the formula for molality, which is moles of solute per kilogram of solvent: ( \text{molality} = \frac{\text{moles of NaCl}}{3 \text{ kg of water}} ).
How do you calculate the molality of 10g of NaCI in 2kg of water?
To calculate the molality (m) of a solution, use the formula: [ \text{molality} (m) = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}. ] First, convert the mass of NaCl into moles by using its molar mass (approximately 58.44 g/mol). For 10 g of NaCl, you have: [ \text{moles of NaCl} = \frac{10 , \text{g}}{58.44 , \text{g/mol}} \approx 0.171 , \text{mol}. ] Then, divide the moles by the mass of the solvent (water) in kilograms: [ m = \frac{0.171 , \text{mol}}{2 , \text{kg}} \approx 0.0855 , \text{mol/kg}. ] So, the molality of the solution is approximately 0.0855 mol/kg.
What are the chemical compounds of salt water?
NaCI + H20 NaCI- Sodium Chloride-Salt. H20 is obviously Di-Hydrogen Oxide. Water.
What would need to be done to calculate the molarity of 10 g of NaCl in 2 kg of water?
To calculate the molarity of 10 g of NaCl in 2 kg of water, you would first need to convert the mass of NaCl to moles using its molar mass. Then, calculate the total volume of the solution by considering the density of water (1 kg = 1 L). Finally, divide the moles of NaCl by the volume of the solution in liters to determine the molarity.
Is saline NaCI in water a compound or mixture?
Its a mixture
How much would the freezing point of water decrease if 4 mol of NaCI were added to 1 kg of water?
The van't Hoff factor for NaCl is 2 since it dissociates into 2 ions in water. The freezing point depression constant for water is 1.86 °C kg/mol. By using the formula ΔTf = i * Kf * m, where i is 2, Kf is 1.86, and m is the molality of the solution (4 mol / 1 kg = 4 m), the freezing point of water will decrease by 14.88 °C.
What is the boiling point of this solution if a chemist dissolves 1.3 mol NaCI in a 2.0-kg sample of water assume the pure water boils at 100 and that Kb for water 0.512Cm.)?
To find the boiling point of the solution, we first calculate the molality (m) of the NaCl solution. Molality is defined as moles of solute per kilogram of solvent: ( m = \frac{1.3 , \text{mol}}{2.0 , \text{kg}} = 0.65 , \text{mol/kg} ). Since NaCl dissociates into two ions (Na⁺ and Cl⁻), we multiply the molality by the van't Hoff factor (i = 2) to find the effective molality: ( 0.65 \times 2 = 1.3 , \text{mol/kg} ). The boiling point elevation can then be calculated using the formula ( \Delta T_b = i \cdot K_b \cdot m ), which gives ( \Delta T_b = 2 \cdot 0.512 \cdot 0.65 = 0.6656 , °C ). Therefore, the new boiling point of the solution is ( 100 + 0.6656 \approx 100.67 °C ).
