When methane (CH₄) is added to a hydroxyl group (–OH), it typically does not react directly because methane is a stable molecule and does not readily participate in reactions with hydroxyl groups. However, if the context is a chemical reaction, such as the formation of an alcohol through a substitution reaction, the product would be an alcohol where the hydroxyl group replaces a hydrogen atom in the methane. In this case, the product would be methanol (CH₃OH).
To calculate the energy produced, you need to know the enthalpy change for the reaction. Once you have that information, you can use the equation Q = mcΔT, where Q is the energy produced, m is the mass of CH4, c is the specific heat capacity of CH4, and ΔT is the temperature change.
To determine how many moles of CH4 (methane) are produced along with 11 moles of water, we need the balanced chemical equation for the reaction. In the case of methane production from a reaction like the one involving carbon dioxide and hydrogen (CO2 + 4H2 → CH4 + 2H2O), every mole of CH4 produced yields 2 moles of water. Therefore, if you have 11 moles of water, you would produce 5.5 moles of CH4.
The chemical formula for methane is CH4. It is a simple hydrocarbon gas that is the main component of natural gas and is produced by the decomposition of organic matter.
For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
The balanced chemical equation for the reaction of CH4 and O2 to produce CO2 is: CH4 + 2O2 -> CO2 + 2H2O First, calculate the limiting reactant by converting the given masses of CH4 and O2 to moles. Then, use the stoichiometry of the reaction to determine the maximum amount of CO2 that can be produced, based on the limiting reactant.
To calculate the energy produced, you need to know the enthalpy change for the reaction. Once you have that information, you can use the equation Q = mcΔT, where Q is the energy produced, m is the mass of CH4, c is the specific heat capacity of CH4, and ΔT is the temperature change.
To determine how many moles of CH4 (methane) are produced along with 11 moles of water, we need the balanced chemical equation for the reaction. In the case of methane production from a reaction like the one involving carbon dioxide and hydrogen (CO2 + 4H2 → CH4 + 2H2O), every mole of CH4 produced yields 2 moles of water. Therefore, if you have 11 moles of water, you would produce 5.5 moles of CH4.
CH4 + 2O2 --> CO2 + 2H2O
Methane, CH4, natural gas.
The chemical formula for methane is CH4. It is a simple hydrocarbon gas that is the main component of natural gas and is produced by the decomposition of organic matter.
CH4 is non polar and water is polar.So they do not mix up
For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
The balanced chemical equation for the reaction of CH4 and O2 to produce CO2 is: CH4 + 2O2 -> CO2 + 2H2O First, calculate the limiting reactant by converting the given masses of CH4 and O2 to moles. Then, use the stoichiometry of the reaction to determine the maximum amount of CO2 that can be produced, based on the limiting reactant.
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
Assuming you are referring to the reaction of CH4 + H2O → CO + 3 H2, and not combustion of methane (CH4 + 2O2 ==> CO2 + 2H2O where NO H2 is formed), then ...100 cm3 CH4 = 0.1 litersmole ratio CH4 : H2 = 1 : 3 (see balance equation above).Liters H2 produced from 0.1 liters CH4 = 3 x 0.1 = 0.3 liters of H2 can be produced.
CH4 is methane, a colorless, odorless gas that is the simplest alkane and the main component of natural gas. It is a greenhouse gas produced by natural processes and human activities, including agriculture and fossil fuel extraction.
For complete combustion of 50 L of gaseous CH4 at STP, you would need 100 L of O2 (in a 1:2 ratio). This is based on the balanced chemical equation: CH4 + 2O2 -> CO2 + 2H2O. The volume of CO2 produced would also be 100 L, as this is also based on the stoichiometry of the chemical reaction.