The formulas you are looking for is I = E/R.
V = IR Voltage = Current * Resistance so 9 = 0.25 * R Hence R =36 Ohms
The resistance of the lamp can be calculated using the formula: Resistance = (Voltage)^2 / Power. Plugging in the values gives: Resistance = (120 V)^2 / 120 W = 120 ohms. So, the resistance of the 120-W incandescent lamp connected to a 120-V power supply is 120 ohms.
I am not sure how the two objects of equal resistance are supposed to be connected. But for a current to flow, for example across a resistor, there must be a voltage difference between the terminals of this resistor.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
Resistance is Volts over Current 11 Ohm = 110Volt / 10 Amp
That depends on the resistance connected. Use Ohm's Law: V=IR. Solving for current: I = V/R. If nothing is connected, there will be no current (infinite resistance).
110volt
in voltmeter we have internal Resistance and connected in series , to current don't transfer in voltmeter , and we have internal resistance in ammeter and connected in parallel , to most current transfer through the ammeter.
Your current will be 30/R Amps. Where R is the resistance in Ohms.
The current depends on what is connected to the battery's terminals. If nothing is connected to it, then there is no current, and the battery lasts quite a while. In general, the current is 1.5/resistance of the external circuit connected to the battery until that number gets too big, and then the voltage of the battery sags, because it can't deliver that much current.
:) It's connected together
I have no idea
Current will be decreased because of the resistance of the ammeter added to the circuit's resistance. In other words total resistance increases.
When resistors are connected in parallel to the same voltage source, the overall resistance in the circuit decreases. This is because the current has multiple paths to flow through, reducing the total resistance that the current encounters.
An ammeter is connected in series. A voltmeter is connected in parallel. ammeter should always be connected in series instead of parallel becoz it is a low resistance device and we know that resistance is inversly proportional to current so more current will pass through it and if it is connected in parallel than it may get damaged
Current equals Voltage divided by Resistance. 9/2=4.5 amps.