The Answer To Your Question Is.... tin (IV) oxide
The chemical formula for Tin IV thiosulfate is Sn(S2O3)4.
Tin(III) Phosphate
The Roman numeral IV in manganese IV sulfide indicates that manganese has a +4 oxidation state in this compound. This means that each manganese atom is contributing four electrons towards bonding with sulfur.
A molecule of tin(IV) oxide (SnO2) contains 2 tin atoms (with 50 neutrons each) and 4 oxygen atoms (with 8 neutrons each). Therefore, the total number of neutrons in a molecule of tin(IV) oxide would be 2 tin atoms x 50 neutrons + 4 oxygen atoms x 8 neutrons = 116 neutrons.
The name for Sn2S4 is tin(IV) sulfide or stannic sulfide.
The chemical formula for tin (IV) sulfide is SnS2.The chemical formula for tin (II) sulfide is SnS.
i think its Sn(SO3)4
The name for SnS2 ionic compound is tin (IV) sulfide. It is formed when the tin ion (Sn^4+) combines with the sulfide ion (S^2-).
SnS2 is the chemical formula of tin(IV) sulfide or tin disulfide.
Lead IV Sulfide is PbS2
When you add sodium sulfide to tin chloride, a precipitation reaction occurs which forms tin sulfide, NaCl, and Na2SO4. Tin sulfide is a solid that precipitates out of solution.
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
The Answer To Your Question Is.... tin (IV) oxide
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
Tin (IV) phosphide
TiS for titanium sulfide (titanium(II) sulfide) and TiS2 for titanium disulfide (titanium(IV) sulfide)