In the reaction ( N_2 + 3H_2 \rightarrow 2NH_3 ), hydrogen gas (( H_2 )) acts as the reducing agent. This is because it donates electrons to nitrogen, reducing its oxidation state. As a result, nitrogen is reduced from an oxidation state of 0 in ( N_2 ) to -3 in ( NH_3 ), while hydrogen is oxidized from an oxidation state of 0 in ( H_2 ) to +1 in ( NH_3 ).
As a rule of thumb, if elemental hydrogen is in a reaction and it's NOT reacting with a metal, it's the reducing agent.
The ion MnO4 is reduced toMnO2 and sulfur is oxidized to ion sulfate. Sulfite is the reducing agent.
The reaction between iodine pentoxide (I2O5) and carbon monoxide (CO) is a redox reaction. In this process, I2O5 acts as an oxidizing agent, while CO serves as a reducing agent. The carbon monoxide reduces the iodine pentoxide, leading to the formation of iodine and carbon dioxide. This type of reaction typically involves the transfer of electrons between the reactants.
In the redox reaction between silver nitrate (AgNO3) and a reducing agent, silver (Ag) is oxidized. This occurs because silver loses electrons during the reaction, leading to its conversion from Ag+ in AgNO3 to elemental Ag. Thus, the element that has been oxidized in this reaction is the silver ion (Ag+).
The ferrous oxide is the oxdant.
As a rule of thumb, if elemental hydrogen is in a reaction and it's NOT reacting with a metal, it's the reducing agent.
In this reaction, Br is the reducing agent because it is being oxidized from Br- to Br2, thereby causing the reduction of Ca from Ca to Ca2+.
The ion MnO4 is reduced toMnO2 and sulfur is oxidized to ion sulfate. Sulfite is the reducing agent.
It is safer to claim it as neither - not least because the reaction would/does not work. Far safer to say that the sulphur is oxidised (which, you could argue, makes it a reducing agent).
Zn alone is a reducing agent because it donates electrons during a reaction and H2SO4 alone is an oxidizing agent because it may donates atomic oxygen during the reaction but (Zn + H2SO4) mixture is a reducing agent because this mixture may produce atomic hydrogen during a reaction.
H2 - hydrogen.
S in (SO4)-2 has a charge of +6, in SO2 S has a charge of +4. To go from +6 to +4 you must gain two electrons. The (SO4)-2 is reduced (reduction is gaining electrons). Therefore it reduces the 2br-, so (SO4)-2 is the reducing agent
In this reaction, FeCl2 is the oxidizing agent because it causes another species to be reduced (lose electrons), while SnCl2 is the reducing agent because it causes another species to be oxidized (gain electrons).
The reaction between iodine pentoxide (I2O5) and carbon monoxide (CO) is a redox reaction. In this process, I2O5 acts as an oxidizing agent, while CO serves as a reducing agent. The carbon monoxide reduces the iodine pentoxide, leading to the formation of iodine and carbon dioxide. This type of reaction typically involves the transfer of electrons between the reactants.
In the redox reaction between silver nitrate (AgNO3) and a reducing agent, silver (Ag) is oxidized. This occurs because silver loses electrons during the reaction, leading to its conversion from Ag+ in AgNO3 to elemental Ag. Thus, the element that has been oxidized in this reaction is the silver ion (Ag+).
In the reaction between 2Li and Fe(C2H3O2)2, lithium (Li) acts as the reducing agent. This is because lithium donates electrons to the iron (Fe) in the iron acetate complex, reducing it from a higher oxidation state to elemental iron. As a result, lithium is oxidized while iron is reduced, producing 2LiC2H3O2 and Fe.
The ferrous oxide is the oxdant.