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One is not necessarily older than the other. It depends on the context. A fault running through any rock must be younger than that rock.

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What granite intrusion crosses a thick sandstone bed which is older and what law is it?

The granite intrusion that crosses a thick sandstone bed is an example of an igneous intrusion that is younger than the sandstone. This relationship is explained by the Law of Cross-Cutting Relationships, which states that geological features that cut through other rocks must be younger than the rocks they cut through. Thus, the granite intrusion is considered younger than the sandstone bed it intersects.


Is the fault older or younger the rock layer A Explain?

To determine whether the fault is older or younger than rock layer A, we can use the principle of cross-cutting relationships. If the fault cuts through rock layer A, it is younger than that layer, as it must have formed after the rock was deposited. Conversely, if rock layer A is found to be disrupted by the fault, then the fault is older. Therefore, examining the relationship between the fault and rock layer A is key to establishing their relative ages.


Why the age of a fault is younger than the rocks in which it is found?

100 year old


Why is the age of a fault in a rock younger in which it is found?

Given the law of superposition and assuming an undisturbed "pancake" stratigraphy each successive layer is younger than the the underlying one. Therefore, the fault is the 'youngest' feature in the system because the rocks need to form first in order for a fault to truncate them.


How can you tell that the sandstone was not deposited on top of basalt layers?

The sandstone layer is older than the basalt. The older rock cannot be on top of the younger rock. The sandstone and the basalt (or basalt dike) are both deposited at the same depth.

Related Questions

Is the sandstone mountain a fault block mountain?

yes it is


What granite intrusion crosses a thick sandstone bed which is older and what law is it?

The granite intrusion that crosses a thick sandstone bed is an example of an igneous intrusion that is younger than the sandstone. This relationship is explained by the Law of Cross-Cutting Relationships, which states that geological features that cut through other rocks must be younger than the rocks they cut through. Thus, the granite intrusion is considered younger than the sandstone bed it intersects.


When there is an igneous intrusion and a fault line which one is younger?

That depends! If the fault line cross cuts the igneous intrusion causing the intrusion to be displaced on either side of the fault and forming a broken mass of rock within the intrusion known as a fault breccia then the fault is younger than the intrusions, as the intrusion must have already existed for the fault to cause it's displacement. If on the other hand the igneous intrusion cross cuts the fault and is un-deformed then it is probable that it is younger than the fault.


Is the fault older or younger the rock layer A Explain?

To determine whether the fault is older or younger than rock layer A, we can use the principle of cross-cutting relationships. If the fault cuts through rock layer A, it is younger than that layer, as it must have formed after the rock was deposited. Conversely, if rock layer A is found to be disrupted by the fault, then the fault is older. Therefore, examining the relationship between the fault and rock layer A is key to establishing their relative ages.


Is the fault older or younger than the layers?

older because it is at the bottom and the ones on top are younger than the bottoms


How does the age of a fault compare to the age of the rocks that are actually faulted?

The fault will be younger than the rocks it faulted (cross-cutting relationships).


Why is the age of a fault younger than the rock in which it is found?

100 year old


Why the age of a fault is younger than the rocks in which it is found?

100 year old


Why is the age of the fault younger than the rocks in which it is found?

100 year old


Why is the age of the fault younger than the rock in which it is found?

100 year old


Why is the age of a fault younger than the rocks in which it is found?

100 year old


Why is a fault younger than the rocks in which it is found?

Faults are the result of "brittle deformation". This means that they occur in rocks which are not molten. A rock has to be solid before it can be faulted, and hence the rock must have formed before the fault could form within it.