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Why is the age of a fault in a rock younger in which it is found?

Given the law of superposition and assuming an undisturbed "pancake" stratigraphy each successive layer is younger than the the underlying one. Therefore, the fault is the 'youngest' feature in the system because the rocks need to form first in order for a fault to truncate them.


What is the relative age of fault or igneous intrusion that cuts through an unconformity?

If a fault or intrusion cuts through an unconformity, the fault or intrusion is younger than all the rocks it cuts through above and below the unconformity.


Is the fault older or younger the rock layer A Explain?

To determine whether the fault is older or younger than rock layer A, we can use the principle of cross-cutting relationships. If the fault cuts through rock layer A, it is younger than that layer, as it must have formed after the rock was deposited. Conversely, if rock layer A is found to be disrupted by the fault, then the fault is older. Therefore, examining the relationship between the fault and rock layer A is key to establishing their relative ages.


Which is younger a fault or sandstone?

One is not necessarily older than the other. It depends on the context. A fault running through any rock must be younger than that rock.


What is the relative age of a fault or igneous intrusion that cuts through an unconformity?

The relative age of a fault or igneous intrusion that cuts through an unconformity is younger than the unconformity but older than the rock it cuts through. This is because the fault or intrusion must have formed after the deposition of the rock layers below the unconformity but before the deposition of the rock layers above the unconformity.

Related Questions

Why is the age of the fault younger than the rocks in which it is found?

100 year old


Why is the age of a fault younger than the rocks in which it is found?

100 year old


Why is a fault younger than the rocks in which it is found?

Faults are the result of "brittle deformation". This means that they occur in rocks which are not molten. A rock has to be solid before it can be faulted, and hence the rock must have formed before the fault could form within it.


Why is the age of a fault is younger than the rocks in which it is found?

How could the rock be faulted if it came after the faulting? It wouldn't be there to fault. So therefore, what ever the fault cuts through, it must be younger than it in order for it to be able to cut the rock in the first place.


Why is the age of a fault younger than the rocks in which it was found?

The fault must be younger because it cuts across the existing rocks, indicating that it formed after the rocks were already in place. This suggests that the faulting event occurred after the deposition of the rock layers.


How does the age of a fault compare to the age of the rocks that are actually faulted?

The fault will be younger than the rocks it faulted (cross-cutting relationships).


It states that fault cut through rocks is always younger than the rocks itcuts?

Yes


Why is the age of a fault in a rock younger in which it is found?

Given the law of superposition and assuming an undisturbed "pancake" stratigraphy each successive layer is younger than the the underlying one. Therefore, the fault is the 'youngest' feature in the system because the rocks need to form first in order for a fault to truncate them.


What is the relative age relationship of faults to the rocks they cut?

Faults are younger than the rocks they cut through, as they are formed after the rock units. The offset layers or rocks along a fault help geologists determine the relative age relationship between the fault and the surrounding rocks.


Why is the age of a fault younger than the rock in which it is found?

100 year old


Why is the age of the fault younger than the rock in which it is found?

100 year old


Which theory explains why rocks found on the ocean floor are younger than found on continents?

Sea Floor Spreading