Ar which stands for Argon. Argon has a filled outer electron shell and won't bind much of anything, so no blame attaches to Mg (Magnesium).
mg p cl ar cr
The atomic symbol for the noble gas with the same electron configuration as Cl⁻ (chloride ion) is Ar, which stands for argon. Chlorine typically has 17 electrons, and when it gains an electron to become Cl⁻, it has 18 electrons, matching the electron configuration of argon. Thus, both Cl⁻ and Ar have a complete octet, characteristic of noble gases.
Arranging in increasing size: Cl- < S2- < K+ < Ca2+. Arranging in increasing ionization energy: K+ < Ca2+ < Cl- < S2-. Electron configurations: Cl-: [Ne]3s^2 3p^6 S2-: [Ne]3s^2 3p^6 K+: [Ar]4s^1 Ca2+: [Ar]4s^2
The order is: O, Cl, Sb, Rb, Ar.
Chlorine (Cl) and Sodium (Na) are likely to form anions by gaining an electron to achieve a stable electron configuration. Neon (Ne) and Argon (Ar) are stable noble gases with a full outer shell and are unlikely to form ions.
mg p cl ar cr
No, Cl (chlorine) and Ar (argon) do not have the same electron configuration. Cl has the electron configuration 1s2 2s2 2p6 3s2 3p5, while Ar has the electron configuration 1s2 2s2 2p6 3s2 3p6. Ar has a full outer shell, making it a noble gas, while Cl is a halogen with one electron short of a full outer shell.
In a Cl-Cl molecule, the atoms are sharing 2 electrons, forming a single covalent bond. Each chlorine atom contributes 1 electron to the bond, resulting in a total of 2 shared electrons between the two atoms.
The bond between Cl and Br is ionic, as Cl is a halogen with a high electronegativity and tends to gain an electron to form a negative ion (Cl-) while Br is a halogen that tends to lose an electron to form a positive ion (Br+).
The atomic symbol for the noble gas with the same electron configuration as Cl⁻ (chloride ion) is Ar, which stands for argon. Chlorine typically has 17 electrons, and when it gains an electron to become Cl⁻, it has 18 electrons, matching the electron configuration of argon. Thus, both Cl⁻ and Ar have a complete octet, characteristic of noble gases.
Arranging in increasing size: Cl- < S2- < K+ < Ca2+. Arranging in increasing ionization energy: K+ < Ca2+ < Cl- < S2-. Electron configurations: Cl-: [Ne]3s^2 3p^6 S2-: [Ne]3s^2 3p^6 K+: [Ar]4s^1 Ca2+: [Ar]4s^2
Li and Cl do not form an ionic bond because Li readily loses its single valence electron to achieve a stable electron configuration (Li+), while Cl readily gains an electron to achieve a stable electron configuration (Cl-). This leads to the formation of a covalent bond between Li and Cl, where they share electrons to achieve stability.
Among the elements listed: Highest electron affinity: Cl (Chlorine) with an electron affinity of -349 kJ/mol. Lowest electron affinity: Ar (Argon) with an electron affinity of 0 kJ/mol (inerts gases like Ar typically have low electron affinities).
A covalent bond forms between Cl and P. In this bond, the atoms share electrons to achieve a stable electron configuration.
Ionic bond would form between Na and Cl. In this bond, sodium (Na) will transfer an electron to chlorine (Cl) to achieve a stable electron configuration. This results in the formation of Na+ cation and Cl- anion, which are attracted to each other due to their opposite charges, forming an ionic bond.
This type of bond is called an ionic bond. It forms between a metal atom that loses an electron (cation) and a non-metal atom that gains an electron (anion), resulting in the attraction between the oppositely charged ions.
bond energy (in kJ/mol) F-F:158 Cl-Cl: 244 Hence, in order of decreasing bond strength: Cl-Cl => => (F-F) => Fluorine is an anomaly. Bond strength decreases from chlorine to iodine as down the group, the atomic size becomes larger and thus the valence electron orbitals become more diffused, causing the overlap of orbitals to become less effective. Therefore the halogen-halogen bond becomes weaker. Fluorine is an exception due to its extremely small size. The F-F bond length is so short that the lone pairs of electrons on the fluorine atoms repel each other and weakens the F-F bond. I hope that answers your question.