A male can inherit an autosomal recessive disorder from both of his carrier parents, who each pass down a copy of the mutated gene. This results in the male having two copies of the mutated gene, leading to the manifestation of the disorder.
Yes, red-green color blindness is typically an X-linked recessive disorder. This means that the gene responsible for red-green color blindness is located on the X chromosome, and individuals who inherit an abnormal gene on their X chromosome are more likely to express the trait if they are male, as they have only one X chromosome.
A male inherits his X chromosome from his mother and his Y chromosome from his father. Therefore, he cannot inherit an X-linked recessive gene directly from his dad, as fathers pass their Y chromosome to their sons. If a male has an X-linked recessive condition, it must come from his mother, who can pass on the affected X chromosome. In summary, males inherit X-linked traits only from their mothers.
Y chromosome is autosomal dominant chromosome. When it is present, the sex of the child is male. When both the chromosomes are X, then the sex of the child is female. X chomosome is called as autosomal recessive chromosome.
Cystic Fibrosis has an autosomal recessive pattern of inheritance, therefore, neither male nor female is more likely to inherit the disease. There are four different scenarios that can occur to "pass on" the disease. First, both parents have CF, and in this scenario all offspring would have CF as well. Second, One parent has CF and the other doesn't. This scenario has two subgroups. The parent that does not have CF could either be a carrier or have no CF gene. If the non-CF parent is a carrier then 3 out of 4 children would inherit CF. If the non-CF parent is not a carrier then 2 of 4 children would inherit it. Third, both parents are carriers, and in this scenario 2 of 4 offspring would inherit CF. Fourth, one parent is a carrier and the other is not. This would yield 1 out of 4 offspring inheriting CF. The genes for CF are located on non-sex chromosomes (autosomes) and therefore there is no correlation to Cystic Fibrosis and sex.
Male hemophiliacs inherit it from their mother, because hemophilia is only on the X gene and males only have one and it is from their mother.
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There is no possibility that a male will inherit and X-linked recessive allele from his father because for a male child the father only contributes the Y chromosome to his son (of the XY pair he has). If the fater's X chromosome has a recessive allele then it is 100% certain that he will pas this on to all his daughters.
Yes, red-green color blindness is typically an X-linked recessive disorder. This means that the gene responsible for red-green color blindness is located on the X chromosome, and individuals who inherit an abnormal gene on their X chromosome are more likely to express the trait if they are male, as they have only one X chromosome.
A male inherits his X chromosome from his mother and his Y chromosome from his father. Therefore, he cannot inherit an X-linked recessive gene directly from his dad, as fathers pass their Y chromosome to their sons. If a male has an X-linked recessive condition, it must come from his mother, who can pass on the affected X chromosome. In summary, males inherit X-linked traits only from their mothers.
Y chromosome is autosomal dominant chromosome. When it is present, the sex of the child is male. When both the chromosomes are X, then the sex of the child is female. X chomosome is called as autosomal recessive chromosome.
Cystic Fibrosis has an autosomal recessive pattern of inheritance, therefore, neither male nor female is more likely to inherit the disease. There are four different scenarios that can occur to "pass on" the disease. First, both parents have CF, and in this scenario all offspring would have CF as well. Second, One parent has CF and the other doesn't. This scenario has two subgroups. The parent that does not have CF could either be a carrier or have no CF gene. If the non-CF parent is a carrier then 3 out of 4 children would inherit CF. If the non-CF parent is not a carrier then 2 of 4 children would inherit it. Third, both parents are carriers, and in this scenario 2 of 4 offspring would inherit CF. Fourth, one parent is a carrier and the other is not. This would yield 1 out of 4 offspring inheriting CF. The genes for CF are located on non-sex chromosomes (autosomes) and therefore there is no correlation to Cystic Fibrosis and sex.
http://www.emedicine.com/derm/topic692.htm Postaxial hand polydactyly is a common isolated disorder in African black and African American children, and autosomal dominant transmission is suspected. Postaxial polydactyly is approximately 10 times more frequent in blacks than in whites and is more frequent in male children. In contrast, postaxial polydactyly seen in white children is usually syndromic and associated with an autosomal recessive transmission.
Male hemophiliacs inherit it from their mother, because hemophilia is only on the X gene and males only have one and it is from their mother.
This is inherited on the X chromoseome and is recessive. This means a female (who has XX chromosome pair) can only express the disease if she carries the trait on both chromosomes. This is because of the recessive nature of the gene. A male can only inherit the disease from his mother. This is he must have obtained his Y chromosome from his father so he obtains the X chromosome from his mother. A male cannot carry the gene without expressing it as he doesnt have another X chromosome to supress the recessive gene. ^ This answer is biologically incorrect because Sickle cell Anemia is actually autosomal recessive, not sex-linked recessive; this means that males and females are affected equally and it is NOT carried on the X chromosome. In order for the trait to show up in an individual, BOTH parents must be carriers of the disease (at least 1 sickle cell gene must be present).
Yes
This is inherited on the X chromoseome and is recessive. This means a female (who has XX chromosome pair) can only express the disease if she carries the trait on both chromosomes. This is because of the recessive nature of the gene. A male can only inherit the disease from his mother. This is he must have obtained his Y chromosome from his father so he obtains the X chromosome from his mother. A male cannot carry the gene without expressing it as he doesnt have another X chromosome to supress the recessive gene. ^ This answer is biologically incorrect because Sickle cell Anemia is actually autosomal recessive, not sex-linked recessive; this means that males and females are affected equally and it is NOT carried on the X chromosome. In order for the trait to show up in an individual, BOTH parents must be carriers of the disease (at least 1 sickle cell gene must be present).
An affected male will typically have one copy of the disease-causing allele, often represented as "X^A Y" for X-linked recessive disorders or "Aa" for autosomal dominant disorders on a pedigree chart. This genotype indicates that the male has one copy of the mutated gene leading to the disease.