Ag is the element Silver. Ag has more electrons than Ag+as for the element to become positively charged through a process called oxidation in which Ag has given up an electron to another element in order to obtain a positive charge. Another way to look at it is the "+" indicates a loss of a negatively charged particle which, in this case, is an electron.
Proper Half-Reaction:
Ag+ + e- ---> Ag
In the given redox reaction, silver nitrate (AgNO3) reacts with sodium nitrate (NaNO3) and elemental silver (Ag). The element that has been reduced is silver (Ag) because it is being converted from its ionic form (Ag^+) in AgNO3 to its elemental form (Ag). Reduction involves the gain of electrons, and in this case, Ag^+ gains an electron to become neutral Ag.
In the redox reaction between silver nitrate (AgNO3) and a reducing agent, silver (Ag) is oxidized. This occurs because silver loses electrons during the reaction, leading to its conversion from Ag+ in AgNO3 to elemental Ag. Thus, the element that has been oxidized in this reaction is the silver ion (Ag+).
Ag+
Silver (Ag)
Yes, Cr³⁺ can oxidize silver (Ag) under certain conditions. Chromium in the +3 oxidation state can act as an oxidizing agent, meaning it can accept electrons from silver, which would be oxidized to Ag⁺. This reaction depends on the specific conditions and concentrations of the reactants involved.
If Ag+ is converted to Ag, it has gained electrons. Ag+ indicates that silver has lost one electron, so when it is converted back to Ag, it means that electron has been gained back.
The number of protons in a atom is equal to the atomic number, therefor Ag has 47 protons. The number of protons and neutrons in an atom is equal to the atomic mass, therefor (108-47= 61) Ag has 61 neutrons. The number of electrons is equal to the number of protons therefor Ag has 47 electrons.
In the redox reaction, silver (Ag) has been reduced because it gains electrons in forming solid silver (Ag) from silver nitrate (AgNO3).
In the redox reaction AgNO3 + NaNO3 + Ag, silver (Ag) is reduced from Ag+ to Ag with the gain of one electron. Therefore, one electron is transferred in this reaction.
In the given redox reaction, silver nitrate (AgNO3) reacts with sodium nitrate (NaNO3) and elemental silver (Ag). The element that has been reduced is silver (Ag) because it is being converted from its ionic form (Ag^+) in AgNO3 to its elemental form (Ag). Reduction involves the gain of electrons, and in this case, Ag^+ gains an electron to become neutral Ag.
In this reaction, silver (Ag) has been oxidized. This is because silver changes from an oxidation state of 0 in Ag metal to an oxidation state of +1 in AgNO3. Oxidation involves the loss of electrons.
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
In the redox reaction between silver nitrate (AgNO3) and a reducing agent, silver (Ag) is oxidized. This occurs because silver loses electrons during the reaction, leading to its conversion from Ag+ in AgNO3 to elemental Ag. Thus, the element that has been oxidized in this reaction is the silver ion (Ag+).
Zero The oxidation number of an element in its elemental form is always zero.
Silver is a metal element. Atomic mass number of it is 197.
In the reaction ( 2Ag^{+} + 2e^{-} \rightarrow 2Ag ), two electrons are transferred per silver ion, so a total of four electrons are transferred in the overall reaction.
Ag+