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2-methylpropanol does not form a yellow precipitate with iodine in NaOH because it is a tertiary alcohol, which does not undergo the iodine test reaction typically associated with primary and secondary alcohols. The reaction involves the formation of iodoforms, which requires the presence of a hydrogen atom on the carbon adjacent to the hydroxyl group. Since 2-methylpropanol lacks this structure, it does not produce the necessary iodoform compound, resulting in no yellow precipitate.
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Why when mixing NaOH plus CuSO4 will become solid and blue deposition.?
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
NaOH(aq) plus FeBr3(aq) and rarr Express your answer as a chemical equation. Enter noreaction if no precipitate is formed.?
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
What is the solution of NaOH in methyl orange indicator?
The solution of NaOH in methyl orange indicator will turn from yellow to red. Methyl orange is an acid-base indicator that changes color in response to a change in pH. In the presence of a strong base like NaOH, the indicator will change to a red color indicating the basic nature of the solution.
When aqueous solutions of iron(III) sulfate (Fe2(SO4)3) and sodium hydroxide were mixed a precipitate formed. What is the precipitate?
When aqueous solutions of iron(III) sulfate (Fe2(SO4)3) and sodium hydroxide (NaOH) are mixed, a precipitate of iron(III) hydroxide (Fe(OH)3) forms. This occurs due to the reaction between the iron(III) ions and hydroxide ions, leading to the formation of the insoluble hydroxide. The balanced chemical equation for the reaction is: Fe2(SO4)3 + 6 NaOH → 2 Fe(OH)3 (s) + 3 Na2SO4.
What happens when you add NaOH solution to a solution ZnCl2?
When you add NaOH solution to a ZnCl2 solution, a precipitation reaction occurs. The hydroxide ions (OH⁻) from the NaOH react with zinc ions (Zn²⁺) to form zinc hydroxide (Zn(OH)₂), which is an insoluble white precipitate. This reaction can be represented by the equation: ZnCl₂ + 2 NaOH → Zn(OH)₂ (s) + 2 NaCl. Over time, the zinc hydroxide may further dehydrate to form zinc oxide.
When NaOH (aq) is added to MgSO4 (aq) a white precipitate forms. What is the precipitate?
The white precipitate formed when NaOH (aq) is added to MgSO4 (aq) is magnesium hydroxide (Mg(OH)2).
What will be the product of the reaction of ethanol and NaOH and iodine?
The reaction of ethanol with NaOH and iodine will yield iodoethane (ethyl iodide) as the product. The alcohol group in ethanol will be replaced by the iodine atom in the presence of NaOH.
Is a precipitate in reaction CuCl2 plus NaOH - and gt Cu (OH)2 plus NaCl?
Copper hydroxide is the precipitate.
Will a precipitate form if solutions of the soluble salts AgNO3 and NaOH are mixed?
Yes, a white precipitate of silver hydroxide (AgOH) will form when solutions of silver nitrate (AgNO3) and sodium hydroxide (NaOH) are mixed. Silver hydroxide is insoluble in water, so it will precipitate out of the solution.
Why is NaOH added in starch iodine test?
In the starch-iodine test, NaOH is added to create an alkaline environment that allows for the formation of the blue-black complex between starch and iodine. This complex is used as an indicator to detect the presence of starch in a sample.
Benzoic acid plus NaOH plus iodine?
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
NaOH(aq) plus FeBr3(aq) and rarr?
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
What type of nutrient can be detected using iodine solution?
Iodine solution is commonly used to detect the presence of starch. When iodine solution comes into contact with starch, it changes color from brownish-yellow to a blue-black color. This color change is a positive indication of the presence of starch in a substance.
What cations will form a precipitate when mixed with a solution of sodium hydroxide NaOH K Mg or Na Ions?
When mixed with a solution of sodium hydroxide (NaOH), a precipitate will form with magnesium (Mg) cations. The magnesium hydroxide formed is sparingly soluble in water, leading to the precipitation reaction. Potassium (K) and sodium (Na) cations do not precipitate when mixed with NaOH as their hydroxides are highly soluble in water.
If Solutions of SrCl2 and NaOH are mixed the result is a precipitate of?
The result is a precipitate of Sr(OH)2 as it is insoluble in water. This reaction forms a white precipitate.
What will NaOh and LiCl combine with to produce precipitate?
Precipitate forms when an INSOLUBLE substance is formed. That means you're looking for ions that form insoluble substances when combined with NaOH and LiCl. That means the ions below are all contenders (use the solubility rules): Ag+ Hg+ Pb2+ Note: PbCl2 is SLIGHTLY soluble in HOT water, but in standard conditions, PbCl2 is considered as insoluble. hope this helps.
Why when mixing NaOH plus CuSO4 will become solid and blue deposition.?
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
