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My guess is that barium sulfate is not toxic because it hardly dissolves at all in water and therefore doesnt easily access the bloodstream. (Ksp value: 1.1*10-10) On the other hand, a lot of barium ions can be present in an aquous solution and they can easily access the bloodstream if they enter the body.

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Why is barium compound toxic?

Barium is not poisonous in the form of its sulfate. That's because barium sulfate is insoluble in water. Unless a barium compound dissolves with the subsequent release of barium ions, it is not going to be highly toxic.


What the spectator ions in silver sulfate plus Barium nitrate reaction?

The spectator ions are Ag+ and (NO3)-.


How can you drink barium ions without dying?

Barium solutions (which contain barium ions) are toxic. As regards drinking them, it's a very bad idea. But as the question is being asked in conjunction with X-ray and Medical Technologies categories, the query may be directed at the use of barium as a contrast agent. Barium sulfate, which is used for contrast in some imaging, is insoluble in water, which is the way it is given, and that means no barium ions. That allows its use without actually poisoning a patient. The compound is, however, something that the body doesn't like, and it can leave a patient with some gastrointestinal issues after it is taken. These issues are not generally severe, and that makes the use of barium sulfate relatively safe for use as prescribed.


How do you test for barium ions in a solution?

Add a sulfate solution: BaSO4 precipitates!


How would you test the presence of sulfate ions?

To identify the presence of sulfate ions in a solution, follow these steps: To acidify the sample, add a few drops of dilute hydrochloric acid (HCl) to the sample. Then, add a few drops of dilute barium chloride (BaCl2) solution to the sample. If sulfate ions are present in the solution, a white precipitate of barium sulfate (BaSO4) will form. The reaction is: Ba²⁺ (aq) + SO4²⁻ (aq) → BaSO4 (s) For example, if we have a solution of magnesium sulfate (MgSO4), the reaction would be: BaCl2 (aq) + MgSO4 (aq) → BaSO4 (s) + MgCl2 (aq) By observing the formation of the white precipitate, we can confirm the presence of sulfate ions in the sample.

Related Questions

Why is barium compound toxic?

Barium is not poisonous in the form of its sulfate. That's because barium sulfate is insoluble in water. Unless a barium compound dissolves with the subsequent release of barium ions, it is not going to be highly toxic.


Why is barium carbonate toxic while barium sulphate is not?

Barium sulfate is insoluble in water, while barium carbonate will dissolve. As barium carbonate dissolves in water, it dissociates, and the barium ions are freed. The barium ions are toxic, and that is the crux of the issue.


What is the test for barium ions?

The test for barium ions involves adding a solution of a sulfate compound (e.g. sodium sulfate) to a solution containing the barium ions. A white precipitate of barium sulfate forms if barium ions are present.


Will a precipitate form if solutions of potassium sulfate and barium nitrate are combined?

Yes, a precipitate of barium sulfate will form because barium ions (Ba²⁺) from barium nitrate react with sulfate ions (SO₄²⁻) from potassium sulfate to form an insoluble compound, barium sulfate (BaSO₄). This insoluble compound will precipitate out of solution.


What are the spectator ions in silver sulfate plus barium nitrate reaction?

The spectator ions in the reaction between silver sulfate and barium nitrate are nitrate (NO3-) ions and sulfate (SO4^2-) ions. These ions do not participate in the formation of the precipitate (barium sulfate) and remain unchanged throughout the reaction.


What precipitate is produced when aluminum sulfate and barium chloride react?

When aluminum sulfate and barium chloride react, the precipitate formed is barium sulfate (BaSO4). This is because barium sulfate is insoluble in water, leading to its precipitation upon mixing with the two solutions.


Why is Barium Sulphate used in the limit test for sulphates?

Barium sulfate is used in the limit test for sulphates because it forms a highly insoluble precipitate with sulfate ions. This property allows for the qualitative or quantitative determination of sulfate ions in a sample by measuring the amount of barium sulfate precipitate formed. The formation of a white precipitate confirms the presence of sulfate ions in the sample.


What is the precipitating agent used to precipitate sulfate?

Barium chloride is commonly used as a precipitating agent to precipitate sulfate ions as insoluble barium sulfate. This reaction is often utilized in analytical chemistry to detect the presence of sulfate ions in a solution.


What anion barium salt is insoluble in water but its copper salt is soluble?

Barium sulfate is insoluble in water, while copper sulfate is soluble. This is due to differences in the solubility rules for these ions in water. Barium sulfate forms a highly insoluble precipitate, while copper sulfate dissociates into its ions in water.


Does barium sulphite precipitate when barium chloride is added to sodium sulphite solution?

Yes, barium sulfate precipitates when barium chloride is added to a sodium sulfite solution due to a double displacement reaction where barium ions from barium chloride react with sulfite ions from sodium sulfite to form a insoluble barium sulfate precipitate.


What is the formula unit for potassium sulfate and barium chloride are mixed to form potassium chloride and barium sulfate?

The balanced chemical equation for this reaction is K2SO4 + BaCl2 → 2KCl + BaSO4. The formula unit shows the ratio of ions combining to form the products: 2 potassium ions combine with 1 sulfate ion to form potassium sulfate, while 1 barium ion combines with 2 chloride ions to form barium chloride.


What is the molecular equation of copper II sulfate barium chloride?

The molecular equation for the reaction between copper (II) sulfate and barium chloride is: CuSO4 + BaCl2 -> BaSO4 + CuCl2. In this reaction, the copper (II) ions switch places with the barium ions to form barium sulfate and copper (II) chloride.