"cacl" does not exist because it is likely a misspelling or a non-existent command. It could be a typo for "calc" which stands for calculator, but without further context, it is difficult to provide a specific answer. Please provide more information for a better response.
The name of Cacl is calcium Chloride
it is a salt and therefore ionic is is however slightly soluble in polar solutions
To find the total ions in 347 g of CaCl₂, first calculate the number of moles of CaCl₂ using its molar mass, which is approximately 110.98 g/mol. Dividing 347 g by the molar mass gives about 3.13 moles of CaCl₂. Each formula unit of CaCl₂ dissociates into one calcium ion (Ca²⁺) and two chloride ions (Cl⁻), totaling three ions per formula unit. Therefore, the total number of ions is 3.13 moles × 3 ions/mole = approximately 9.39 moles of ions, or about 5.65 × 10²⁴ ions.
bLeaching powder (not 'beaching' ! ) is sodium hypochlorite, NaClO or calcium hypochlorite, CaCl(OCl) or a mixture of both.
Yes, calcium chloride (CaCl2) is soluble in water. It is highly soluble and forms a clear solution when added to water.
The name of Cacl is calcium Chloride
Calcium chloride (chemical formula CaCl) is a salt. it can be a solid, or it can be dissolved in water.
That answer is CaCl
CaCl
To prepare a 25 mL solution of 2M calcium chloride (CaCl₂), you need to calculate the amount of CaCl₂ required. First, use the formula: [ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} ] For a 2M solution in 0.025 L (25 mL), you need 0.05 moles of CaCl₂. The molar mass of CaCl₂ is approximately 110.98 g/mol, so you would weigh out about 5.55 grams of CaCl₂ and dissolve it in enough water to make a final volume of 25 mL.
1
Cacl^2
Not a clue, but CaCl2 is calcium chloride.
No, because it can't exist. +1 is not a possible oxidation state for calcium.
I don't know at all it has ben unanswered
Calcium chloride, CaCl
it is a salt and therefore ionic is is however slightly soluble in polar solutions