This is the Boyle-Mariotte law !
Boyle's Law is represented by the equation PV = k, where P is pressure, V is volume, and k is a constant when temperature is held constant. This law states that the pressure of a gas is inversely proportional to its volume.
Assuming it's a bag of gas at constant temperature, four times the volume by the relationship: P1V1 = P2V2
P1V1=P2V2 VI=325ml P1=655mm Hg V2=125ml P2=? =655 x 325= P2 x 125 =(655 x 325)/ 125 =212875/125 =1703mm Hg. :)
Using the ideal gas law (PV = nRT) and since the temperature is constant, the initial and final conditions of the gas can be related through (P1V1) = (P2V2). Given: P1 = 0.93 atm V1 = 9.00 m^3 P2 = 1 atm (standard pressure) V2 = unknown Rearranging the equation to solve for V2 gives: V2 = (P1V1) / P2 Substitute the values and solve: V2 = (0.93 atm * 9.00 m^3) / 1 atm V2 = 8.37 m^3 Therefore, the volume of the gas at standard pressure is 8.37 m^3.
Using Boyle's Law (P1V1 = P2V2), we can find the final volume of the gas. Given P1 = 0.970 ATM, V1 = 594 mL, and P2 = 0.541 ATM, we can solve for V2. Rearranging the formula gives V2 = (P1V1)/P2 = (0.970594)/0.541 = 1063.95 mL. Therefore, the final volume of the gas is 1063.95 mL when its pressure reaches 0.541 ATM.
P1v1=p2v2
Avogardo's Law
Boyle's law states this fact.
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
Boyle's Law is represented by the equation PV = k, where P is pressure, V is volume, and k is a constant when temperature is held constant. This law states that the pressure of a gas is inversely proportional to its volume.
The general representation of the combined gas law is P1V1/T1 = P2V2/T2
P1V1 = P2V2, so 1480 litres in this case.
Possibly: P1V1 = P2V2 or: increase volume => lower pressure (thinking of the kinetic model)
Possibly: P1V1 = P2V2 or: increase volume => lower pressure (thinking of the kinetic model)
The question is incomplete and unanswerable as written
Because it is so high up the air. Pressure up there is high and temperature therefore low if you use P1V1/T1= P2V2/T2
P1V1=P2V2 P1V1/T1=P2V2/T2 PV=nRT P=pressure V=volume n=number of moles R=the gas constant 8.31J/molK or 0.0821Latm/molK T=temperature in kelvin