Cuprous ions (Cu+) have a partially filled d orbital, making them prone to oxidation to Cu2+ in order to achieve a more stable d10 electron configuration. On the other hand, cupric ions (Cu2+) have a full d orbital, resulting in greater stability due to the filled electron subshell.
The ratio of Cu ions (Cu2+) to sulfide ions (S2-) in copper sulfide (Cu2S) is 1:1, meaning for every Cu2+ ion there is one S2- ion. This results in a 1:1 ratio of Cu2+ to S2-.
Cu2 + 2OH --> 2CuOH
The electron configuration of Cu+1 is [Ar] 3d10 4s1. When copper loses one electron to become a +1 ion, it loses the 4s electron first, followed by one of the 3d electrons to attain a stable electron configuration.
No. This is a redox question. It is asking whether the reaction will occur spontaneously. In order for Mg+2 to spontaneously oxidize Cu(s), Mg+2 needs to have a higher reduction potential (the tendency to be reduced) than Cu+2. Check a redox table to see: Mg2+ + 2 e− --> Mg(s) E° = −2.372 Cu2+ + 2 e− --> Cu(s) E° = +0.340 (More favorable reaction) Cu2+ has a higher reduction potential, meaning Mg2+ will not oxidize Cu(s).
Cu2+ is more stable, though Cu+ compounds are known
Cu2 is more active than Cu in chemical reactions because Cu2 has a higher oxidation state, meaning it has more electrons available for bonding and reacting with other substances. This makes Cu2 more likely to participate in reactions and form compounds compared to Cu.
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
Cuprous ions (Cu+) have a partially filled d orbital, making them prone to oxidation to Cu2+ in order to achieve a more stable d10 electron configuration. On the other hand, cupric ions (Cu2+) have a full d orbital, resulting in greater stability due to the filled electron subshell.
Cu2+ is a cation as are all positive ions. One way to remember is to think of the "t" in cation as a plus sign.
Cu-------Cu2+ + 2 e-
The ionic equation for copper(II) nitrate solution (Cu(NO3)2) is: Cu2+(aq) + 2NO3-(aq) -> Cu(NO3)2(aq)
Cu(ClO4)2 dissociates into Cu2+ ions and 2 ClO4- ions in solution. This results in the breakdown of the copper perchlorate compound into its constituent ions when dissolved in water. The balanced equation for the dissociation of Cu(ClO4)2 is: Cu(ClO4)2 -> Cu2+ + 2 ClO4-.
The ratio of Cu ions (Cu2+) to sulfide ions (S2-) in copper sulfide (Cu2S) is 1:1, meaning for every Cu2+ ion there is one S2- ion. This results in a 1:1 ratio of Cu2+ to S2-.
Many elements on the periodic table got there chemical symbol from the latin name of the element. For example. Copper's chemical symbol is Cu, even though there is no u in copper. This is because in latin, Copper is "cuprum." Cuprum is Copper, which has the symbol Cu.
Cu2 + 2OH --> 2CuOH
Elemental, or metallic copper, has the formula of Cu. The most common copper cation is Copper (II), or Cu2+, however, copper can also exist in oxidation states +1, +3, and +4, which would be Cu+, Cu3+, and Cu4+, respectively.