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What else can I help you with?
What are the instrument used in measuring the mass of water?
Instruments used to measure the mass of water include a balance scale, a digital scale, and a spring scale. These tools are commonly used in laboratories and industrial settings to accurately determine the weight of water samples.
When a cell is bathed in fluids but you notice water flowing out of the cell what kind of solution is this cell immersed?
When a cell is bathed in fluids and water flows out of the cell, it is immersed in a hypertonic solution. In a hypertonic environment, the concentration of solutes outside the cell is higher than inside, causing water to move out to balance the solute concentrations. This results in the cell shrinking or undergoing crenation.
If A spherical ball is immersed in water contained in a vertical cylinder how do you Calculate the rise in the level of the water?
To calculate the rise in the water level when a spherical ball is immersed in water in a vertical cylinder, you can use the Archimedes' principle, which states that the buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. The volume of water displaced by the ball is equal to the volume of the ball. Calculate the volume of the ball using the formula for the volume of a sphere, then use this volume to determine the rise in water level.
If plant cells are immersed in distilled water the resulting movement of water into the cells is called?
The movement of water into plant cells when they are immersed in distilled water is called osmosis. Osmosis is the diffusion of water molecules across a selectively permeable membrane from an area of higher water concentration to an area of lower water concentration.
What is a symbol for immersed?
A common symbol for being immersed in something might be a person submerged in water or surrounded by waves to represent a deep involvement or engagement in a particular activity or environment.
A solid is 40 Newton when immersed totally in a liquid of relative density 0.8. calculate the weight when immersed in water?
The buoyant force acting on the solid in the liquid is 40 N, which is equal to the weight of the liquid displaced. The weight of the solid in water can be calculated by using the relative densities of water and the liquid (0.8) in the relation: weight in water = weight in liquid * (relative density of liquid / relative density of water).
How do you find the weight of the equal volume of water that buoys up the immersed stone when it is immersed?
you can use a 300ml graduated cylinder water,3different objects
If a body is immersed in water will the weight of the body increase?
No, the weight of the body will not increase when immersed in water. The weight of an object is determined by the force of gravity acting on it, which remains constant regardless of whether the object is in water or in air. The apparent weight of the body will be less in water due to the buoyant force acting on it.
What is the weight of 1 Kg gold immersed in water?
51 gram == 1.8 oz
How can we determine upthrust using Archimede's principle?
The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced
Why and how does a body lose weight when it is immersed in water?
When a body is immersed in water, it experiences buoyant force which reduces its weight. This results in a decrease in apparent weight, which can be misinterpreted as weight loss. However, the actual mass of the body remains the same as the buoyant force only affects the apparent weight.
How does weight of an object immersed in a liquid affect the buoyant force on the object?
Not at all. (The buoyancy force equals the weight if the displaced water,)
Why does object immersed in water loses apparent weight not complete weight?
When an object is immersed in water, it experiences an upward force known as buoyancy due to the displaced water. This buoyant force reduces the net force acting on the object, causing it to lose apparent weight. However, the object still has its complete weight acting downward, but the buoyant force counteracts a portion of it, leading to the apparent weight being less than the actual weight.
Why is it easier to lift a heavy stone when fully immersed in water?
Because an object immersed in water is buoyed upward by a force equal to the weight of the displaced water, so the stone's net weight in water is less than it is in air, by a difference of roughly 62 pounds for each cubic foot of its volume.
What buoyancy mean?
Non-buoyancy means that an object does not float (I think).
Ships float submarines sink?
Submarines can go downward because they flood their buoyancy tanks with water. This reduces the buoyancy of the sub, allowing it to go down. To rise again, the water is pumped out of these tanks.
What is the apparent mass in water?
The apparent mass in water refers to the apparent weight of an object when immersed in water. This weight is equal to the difference between the actual weight of the object in air and the buoyant force acting on it while submerged in water.
