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What is apparent relative density?
Apparent relative density is a measure of the density of a material compared to the density of another reference material, typically water. It is calculated by dividing the apparent mass of the material by the mass of an equal volume of the reference material. Apparent relative density does not take into account the presence of any voids or pores in the material.
What is the apparent weight formula and how is it used to calculate the apparent weight of an object in different gravitational environments?
The apparent weight formula is: Apparent Weight Actual Weight - (Mass x Acceleration due to Gravity). This formula is used to calculate the apparent weight of an object in different gravitational environments by taking into account the mass of the object and the acceleration due to gravity in that specific environment. By plugging in the values for mass and acceleration due to gravity, you can determine the apparent weight of the object in that particular gravitational setting.
What is the apparent depth of an object whose real depth below the water surface is 5 m?
The apparent depth of an object submerged in water can be calculated using the formula: apparent depth = real depth / refractive index. Since the refractive index of water is approximately 1.33, the apparent depth of an object 5 meters below the water surface would be around 3.76 meters.
What is a stone's mass in water?
The mass of a stone in water is the mass of the stone outside water. The mass of an object is always its mass. (This assumes we are not discussing the theory of relativity.) On Earth, or the Moon or in water or not, mass is mass. What might be relevant, however, is the weight of a stone in water compared to the weight of a stone outside the water. Weight and mass are different. If you hold a stone in water and hold the same stone in air, you can feel a difference in the force you must apply to support the stone. In water, the stone feels a buoyant force equal the the weight of the water displaced. That is Archimedes principle. There is a difference in the apparent weight of a stone in water and a stone out of water equal to the eight of the water displaced.
How do you calculate density of irregular shape solid lighter than water?
To find the density of an irregular shape solid lighter than water, you can use the following steps: Weigh the solid in air to determine its mass (m). Weigh the solid while it is fully submerged in water to determine its apparent mass (m'). Calculate the density using the formula: Density = (m / (m - m')) * density of water.
What is apparent relative density?
Apparent relative density is a measure of the density of a material compared to the density of another reference material, typically water. It is calculated by dividing the apparent mass of the material by the mass of an equal volume of the reference material. Apparent relative density does not take into account the presence of any voids or pores in the material.
If an object has a mass of 158.46 kg in air and an apparent mass of 97.52 kg when immersed in water what is the volume and relative density of the object?
volume
What is the apparent weight formula and how is it used to calculate the apparent weight of an object in different gravitational environments?
The apparent weight formula is: Apparent Weight Actual Weight - (Mass x Acceleration due to Gravity). This formula is used to calculate the apparent weight of an object in different gravitational environments by taking into account the mass of the object and the acceleration due to gravity in that specific environment. By plugging in the values for mass and acceleration due to gravity, you can determine the apparent weight of the object in that particular gravitational setting.
How mass and weight similar?
Mass is an intrinsic property of matter. Weight is the apparent weight of a mass under a particular acceleration.
Why is there a weight difference when water freezes and melts?
Water doesn't gain or lose mass when it freezes. Ice is less dense than water, this is why it floats. It may seem heavier, but there is no way that water can gain mass from just losing energy. Water does evaporate though even at very low temperatures, so if there is an apparent weight loss it is because of evaporation.
What is the apparent depth of an object whose real depth below the water surface is 5 m?
The apparent depth of an object submerged in water can be calculated using the formula: apparent depth = real depth / refractive index. Since the refractive index of water is approximately 1.33, the apparent depth of an object 5 meters below the water surface would be around 3.76 meters.
What is a stone's mass in water?
The mass of a stone in water is the mass of the stone outside water. The mass of an object is always its mass. (This assumes we are not discussing the theory of relativity.) On Earth, or the Moon or in water or not, mass is mass. What might be relevant, however, is the weight of a stone in water compared to the weight of a stone outside the water. Weight and mass are different. If you hold a stone in water and hold the same stone in air, you can feel a difference in the force you must apply to support the stone. In water, the stone feels a buoyant force equal the the weight of the water displaced. That is Archimedes principle. There is a difference in the apparent weight of a stone in water and a stone out of water equal to the eight of the water displaced.
Formula to calculate real depth from apparent depth?
Real depth Dr= Apparent depth/ refractive index of water Dr= Da / n water
How do you calculate density of irregular shape solid lighter than water?
To find the density of an irregular shape solid lighter than water, you can use the following steps: Weigh the solid in air to determine its mass (m). Weigh the solid while it is fully submerged in water to determine its apparent mass (m'). Calculate the density using the formula: Density = (m / (m - m')) * density of water.
Why and how does a body lose weight when it is immersed in water?
When a body is immersed in water, it experiences buoyant force which reduces its weight. This results in a decrease in apparent weight, which can be misinterpreted as weight loss. However, the actual mass of the body remains the same as the buoyant force only affects the apparent weight.
What are the sources of error in refractive index of water experiment by apparent method?
Sources of error in the refractive index of water experiment by apparent method may include temperature fluctuations affecting the refractive index of water, impurities in the water affecting the measurement accuracy, and environmental factors like air bubbles or water impurities causing distortion in the apparent depth readings.
Will an object have a greater apparent mass in air or in a vacuum?
The mass remains the same. Apparent mass is only a liquid displacement value. Not a gas or lack of one. Of course if you could float an object on a gas you would have to know the weight of the gas displaced and subtract that from the objects weight to call it apparent mass. The local density of air has little to do with its actual measured mass. Even a sheet of paper would not float in a vacuum.
