Liquid is more dense than air. This causes it to support more weight and require less effort to lift.
The buoyant force is zero when the object is just touching the liquid. As the object displaces more volume, the buoyant force increases until the object is completely submerged. Once the object is submerged, it doesn't matter how deep it is, the buoyant force remains constant.
The buoyant force acts in the opposite direction of gravity, pushing an object upwards when it is submerged in a fluid. This force is proportional to the volume of the displaced fluid by the object and helps objects float or rise in a fluid, enabling objects to achieve buoyancy.
The buoyant force on a submerged object is equal in magnitude to the weight of the water displaced by the object. This principle is known as Archimedes' Principle. It explains why objects float or sink in fluids.
I think you mean a buoyant force. When an object is submerged into a liquid, the liquid pushes up on the object with a force equal to the weight of the amount of fluid that is displaced.
Two ways to do this: 1) Floating the less dense object on the more dense liquid. To verify the Archimedes principle you need to show that the mass of the liquid displaced by the less dense object is equal to the mass of the less dense object. To do this you need to have a way to determine the mass of the displaced liquid. If the liquid is in a container filled to the brim, then when you place the less dense object in it, the displaced liquid will spill out over the edges of the container. If you can collect and weight that liquid, then you can compare its weight to the weight of the less dense object - they should match. Alternatively, you can find a way to measure the volume of the displaced liquid and calculate the mass from the volume and density of the displaced liquid. 2) Immerse the object completely in the liquid and measure the force required to keep it submerged. This one is more complicated and difficult to execute and measure. The force required to keep the less dense object submerged should be the difference between the weight of the object (when it is not in the liquid) and the weight of the displaced liquid.
An object will appear to lose weight when completely submerged in water due to the buoyant force acting on it. This force is equal to the weight of the water displaced by the object, causing it to feel lighter in water compared to in air.
You will find that such an object will weigh its weight on land minus the weight of the water it displaceswhen submerged. It doesn't seem possible, but it is true. This kind of result is called 'counterintuitive'.
A partially submerged object floats when the weight of the water it displaces is equal to its own weight, creating a balance that allows it to remain buoyant. This is known as Archimedes' principle. If the object's weight is greater than the weight of the water it displaces, it will sink, and if the object's weight is less, it will float completely above the water.
mass of fluid, weight of fluid, density of fluid.
The buoyant force is zero when the object is just touching the liquid. As the object displaces more volume, the buoyant force increases until the object is completely submerged. Once the object is submerged, it doesn't matter how deep it is, the buoyant force remains constant.
The buoyant force on a submerged object depends on the volume of the object. It is equal to the weight of the fluid displaced by the object, which is determined by its volume. The weight of the object itself affects the net force experienced by the object when submerged.
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
That completely depends on the object's volume (which you have not mentioned). The buoyant force on it is equal to the weight of an equal volume of water.
The buoyant force on any object in a fluid ... whether partially or fully submerged ... isequal to the weight of the fluid displaced by the object. That's related to the object'svolume, and has nothing to do with its weight.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
No.
Submerged unit weight refers to the weight of soil or material per unit volume when submerged in water, taking into account buoyancy effects. Submerged weight refers to the total weight of an object or material when it is submerged in a fluid, including both its actual weight and any buoyant force acting on it.