Water and octane are practically non miscible.
Octane is less dense than water, so it will float on the surface of water.
The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1 The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g 19.8 g of octane is 114.23/19.8 moles so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water
When soap is mixed with octane the non-polar ends of the soap molecules are attracted with induced-dipole induced-dipole attractions to the non-polar octane molecules. The octane molecules repel the polar ends of the soap and the soap molecules form inverted soap bubbles that attract polar molecules like water.
Octane is a compound. octane + O2 = CO2 + H2O + Energy, You can tell by the inputs and outputs. Octane and Oxygen inputs and Carbon dioxide and water outputs, means Octane must consist of hydrogen H and carbon C, thus a compound not an element.
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Octane is less dense than water, so it will float on the surface of water.
Octane and water do not react and so there is not an equation.
No, it is not possible; also octane is not soluble in water !
Octane + oxygen ---> carbon dioxide + water Lulu
Octane (C8H18) is nonpolar and does not have any functional groups that can interact with water, which is a polar solvent. Therefore, octane is not soluble in water. The lack of attraction between the nonpolar octane molecules and polar water molecules results in poor solubility.
The equation for the dissolution of CO2 in water is: CO2 H2O H2CO3
The two products of the complete combustion of octane are carbon dioxide (CO2) and water (H2O).
The enthalpy of dissolution of NaCl in water is the amount of heat energy released or absorbed when NaCl dissolves in water.
octane + oxygen --> water + carbon dioxide
Dissolution (in water).
The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1 The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g 19.8 g of octane is 114.23/19.8 moles so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water
If you meant C8H18, it is an octane-isomer, than the answer is NO, not miscible with water. Petrol contains a lot (>50%) of octane molecules.