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What would be the empirical formula of octane?
the structural formula for octane(straight chain) is CH3 CH2 CH2 CH2 CH2 CH2 CH2 CH3
Which alkane is used in petrol?
C4H10- Butane C5H12- Pentane C6H14- Hexane C7H16- Heptane C8H18- Octane C9H20- Nonane C10H22- Decane
Ask us anythingOctane (C8H18) is found in gasoline. It is burned for fuel in a combustion reaction. The unbalanced combustion reaction for octane is shown below. C8H18 plus O2 CO2 plus H2O plus heat W?
The balanced combustion reaction for octane would be: 2C8H18 + 25O2 → 16CO2 + 18H2O + heat
What is the whole number coefficient of O2 when the equation for the combustion of C8H18 is completed and balanced?
The combustion reaction of octane is:2 C8H18 + 25 O2 = 16 CO2 + 18 H2OSo, the number of oxygen molecules is 25.The isomer trimethylpentane is used as standard in octane rating: the end of the scale at 100.
Since water is a much smaller molecule than octane C8H18 one would expect it to flow more quickly However studies show that water is almost four times as viscous as octane How can this be explain?
Octane molecules have almost no interaction with each other but water molecules link up together via a process called hydrogen bonding. This increases the viscosity, boiling and melting points for water.
How many moles of are present in 16.0 of octane?
To determine how many moles of octane are present in 16.0 g, you would divide the mass of octane by its molar mass. The molar mass of octane (C8H18) is approximately 114.23 g/mol. Therefore, 16.0 g ÷ 114.23 g/mol = 0.14 moles of octane.
What would be the empirical formula of octane?
the structural formula for octane(straight chain) is CH3 CH2 CH2 CH2 CH2 CH2 CH2 CH3
Which alkane is used in petrol?
C4H10- Butane C5H12- Pentane C6H14- Hexane C7H16- Heptane C8H18- Octane C9H20- Nonane C10H22- Decane
Ask us anythingOctane (C8H18) is found in gasoline. It is burned for fuel in a combustion reaction. The unbalanced combustion reaction for octane is shown below. C8H18 plus O2 CO2 plus H2O plus heat W?
The balanced combustion reaction for octane would be: 2C8H18 + 25O2 → 16CO2 + 18H2O + heat
What is the whole number coefficient of O2 when the equation for the combustion of C8H18 is completed and balanced?
The combustion reaction of octane is:2 C8H18 + 25 O2 = 16 CO2 + 18 H2OSo, the number of oxygen molecules is 25.The isomer trimethylpentane is used as standard in octane rating: the end of the scale at 100.
What would happen to the solubility of potassium choloride in water as the water temperature increased from 25c to 75c?
The solubility of potassium chloride in water typically increases with temperature. Therefore, as the water temperature increases from 25°C to 75°C, the solubility of potassium chloride in water would also increase.
Since water is a much smaller molecule than octane C8H18 one would expect it to flow more quickly However studies show that water is almost four times as viscous as octane How can this be explain?
Octane molecules have almost no interaction with each other but water molecules link up together via a process called hydrogen bonding. This increases the viscosity, boiling and melting points for water.
Who would use octane gas the most?
Octane is a liquid, not a gas. Its boiling point is considerably higher than that of water.
How much co2 is formed from the burning of 1.8 kg of octane?
The formula for normal octane is C8H10. Each mole burned creates 8 moles of CO2. A mole of octane is 106 grams, 8 moles of CO2 is 8x44 = 352 grams So 1.8 kg of octane would produce 1.8x(352/106) = 5.98 g CO2. As the octane value is given to 1 decimal place the answer can be no more accurate so 6.0 kg.
What would happen to the solubility of potassium chloride in water as the water temperature increased from 25C to 100C?
Generally the solubility of solids in liquids increase with the temperature.In this case the solubility increse from 39 g/100 g to 56,3 g/100 g water.
What would happen to the solubility of a gas in water if the volume of the water were decreased but the volume of the gas remained constant?
If the volume of the water is decreased while the volume of the gas remains constant, the solubility of the gas will decrease. This is because a decrease in water volume leads to a decrease in the available space for the gas molecules to dissolve in, resulting in reduced solubility.
Which would you expect to have a greater influence on the effect of a solution in natural water concentration or solubility?
The concentration; to prepare a solution the compound must have a solubility.
