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we all know determining the joule thomson coefficient is determined by performing irreversible adiabatic process, i.e. constant enthalpy process, it may be determined foe any gas .

Since enthalpy remains constant in this process

let h1 be the enthalpy before the irreversible expansion and h2 be the enthalpy after expansion, h1=h2 . for a real gas h enthalpy is a function of pressure and temperature so it may get cooled or get warm according to nature of gas and conditions

but for an ideal gas h=f(T) only since h= u +pv [they both are dependent on absolute temperature] so while going through irreversible expansion the gas does not depend on pressure .

mathematically,

let @ be joule thomson coefficient

$ be parial derivative

@= 1/ cp multiplied by [T multiplied by{$v/$t}at constant pressure -v]

for an ideal gas $v/$T at constant pressure becomes v/T also pv =RT {observe equations are written on per kg basis} so v/T= R/p so we get @=0

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How joule Thomson experiment lead to coefficient?

The Joule Thomson experiment involves measuring the change in temperature of a gas as it expands through a throttle valve. The Joule Thomson coefficient is defined as the temperature change per unit pressure drop. By quantifying the temperature change in relation to the pressure drop, scientists can determine the Joule Thomson coefficient for a specific gas under certain conditions.


When a real gas undergoes joule Thomson expansion how does the temperature react?

The temperature of a real gas can either increase, decrease, or remain constant during Joule-Thomson expansion, depending on the initial conditions such as pressure and temperature. This is due to the interplay between the Joule-Thomson coefficient and the specific heat of the gas.


What are the applications of joule Thomson effect?

The Joule-Thomson effect is used in refrigeration systems to cool gases by expanding them through a small valve. It is also used in natural gas processing to control the temperature of gases during transportation. Additionally, it is utilized in cryogenics to produce low temperatures for scientific research and medical applications.


Why joule Thomson effect is not applicable for hydrogen and hellium?

As the gas flow from high pressure to low pressure using the porous plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume


How do you calculate joule kelvin inversion temperature of hydrogen?

use the T=2a/(bk) equation shown in the first link, plugging in a and b values found in the second link. proofs are shown in the joule-thomson expansion wikipedia page as well as the van der waals equation of state page.

Related Questions

How is the Joule-Thomson effect calculated in thermodynamics?

The Joule-Thomson effect is calculated in thermodynamics by using the Joule-Thomson coefficient, which is the rate of change of temperature with pressure at constant enthalpy. This coefficient is determined by taking the partial derivative of temperature with respect to pressure at constant enthalpy. The formula for the Joule-Thomson coefficient is given by (T/P)H, where is the Joule-Thomson coefficient, T is temperature, P is pressure, and H is enthalpy.


How joule Thomson experiment lead to coefficient?

The Joule Thomson experiment involves measuring the change in temperature of a gas as it expands through a throttle valve. The Joule Thomson coefficient is defined as the temperature change per unit pressure drop. By quantifying the temperature change in relation to the pressure drop, scientists can determine the Joule Thomson coefficient for a specific gas under certain conditions.


What is the value of joule Thomson coefficient for Natural gas?

The Joule-Thomson coefficient for natural gas can vary depending on the specific composition of the gas. Generally, it is around 0.25 K/bar at room temperature and pressure for most natural gas compositions. However, this value can change with different operating conditions and gas compositions.


When a real gas undergoes joule Thomson expansion how does the temperature react?

The temperature of a real gas can either increase, decrease, or remain constant during Joule-Thomson expansion, depending on the initial conditions such as pressure and temperature. This is due to the interplay between the Joule-Thomson coefficient and the specific heat of the gas.


What are the applications of joule Thomson effect?

The Joule-Thomson effect is used in refrigeration systems to cool gases by expanding them through a small valve. It is also used in natural gas processing to control the temperature of gases during transportation. Additionally, it is utilized in cryogenics to produce low temperatures for scientific research and medical applications.


Why joule Thomson effect is not applicable for hydrogen and hellium?

As the gas flow from high pressure to low pressure using the porous plug the temperature of the gas increases as the pressure of the gas decreases. As we know in all this process the enthalpy is constant. As we know in all this process the enthalpy is constant . So, to stay it constant the internal energy increases which lead to increase in temperature of the gas. Formula h=u+pv h--- enthalpy u-- internal energy p--pressure v---volume


How do you calculate joule kelvin inversion temperature of hydrogen?

use the T=2a/(bk) equation shown in the first link, plugging in a and b values found in the second link. proofs are shown in the joule-thomson expansion wikipedia page as well as the van der waals equation of state page.


What is Thompson experiment?

It is an experiment in which the Joule-Thomson coefficient is measured. Basically, you are expanding a gas under adiabatic conditions to ensure constant enthalpy and you will notice that there will be a temperature change (most likely cooling).


Significance of joule Thomson effect?

It is an experiment in which the Joule-Thomson coefficient is measured. Basically, you are expanding a gas under adiabatic conditions to ensure constant enthalpy and you will notice that there will be a temperature change (most likely cooling).


What are the applications of Thomson effects?

two application joule thomson 1. linde methode 2. liquiefied


Do gases cool when they are compressed?

Yes, gases cool when they are compressed because the compression increases the gas's density and reduces its volume, leading to a decrease in internal energy and a corresponding drop in temperature. This phenomenon is known as the Joule-Thomson effect.


What term describes the cooling of a gas by expansion?

Joule-Thomson effect.