The Mohr method is used for the determination of chloride (Cl) and bromide (Br) ions in a solution due to its simplicity and effectiveness in visual titration. It involves the addition of a silver nitrate solution to the sample, which forms a colored precipitate with these halides. The endpoint is indicated by a color change, typically using a chromate indicator that forms a reddish-brown precipitate of silver chromate once all halides are precipitated. This method is advantageous for its accuracy and rapidity in detecting halide concentrations in various samples.
K :- potassiumCl:- ChlorineO:- OxygenBr:- Bromine
The binary compound ClBr is known as bromine monochloride. It consists of one chlorine (Cl) atom and one bromine (Br) atom. This compound can exist in different forms, including as a gas at room temperature, and is used in various chemical applications.
symbol for halide is RX where R can be any element and X can be any element from halogen group like HCl,HBr where H is R and {Cl,Br} is X
Eight electrons in the 2nd shell of Br- This is also the number of electrons in the 2nd shell of I-, Cl- and even F- !
Only four compounds with Cl and Br were obtained up today.
Mohr method is a Precipitation titrations method which is the concentration of an unknown substance in solution is determined by adding measured amount of a standard solution such as AgNO3 that react with unknown samples to determine CL, Br in Solid and solutions samples . NaCL + AgNO3 =====> AgCL + NaNO3. Br- + Ag NO3=====> AgBr + NO3- Then the concentration of the unkown can be calculated using the stoichiometry of the recation and the number of moles of standard solution needed to reach the End point. The mohr method uses chromate CrO4 2- ion as an indicator . By Known the stoichiometry and moles consumed at end point,we can determine the mount of chloride in an unknown samples. Saeed Yousef AL-Soumali
The bond between Cl and Br is ionic, as Cl is a halogen with a high electronegativity and tends to gain an electron to form a negative ion (Cl-) while Br is a halogen that tends to lose an electron to form a positive ion (Br+).
soluble
Br-Cl has a more polar bond because chlorine is more electronegative than iodine, resulting in a greater difference in electronegativity between the two elements. This difference in electronegativity leads to a more polar bond in Br-Cl compared to Br-I.
K :- potassiumCl:- ChlorineO:- OxygenBr:- Bromine
The P-Cl bond is more polar than the P-Br bond. This is because chlorine (Cl) is more electronegative than bromine (Br), so it attracts the shared electrons in the bond more strongly, leading to a greater difference in electronegativity and thus a more polar bond in P-Cl compared to P-Br.
yes it is, because HBr is a stronger acid than HCl, therfore, HBr will have a weaker conjugate base, Br, than HCl, Cl
The S-Cl bond is more polar than the Br-Cl bond. This is because sulfur (S) is more electronegative than bromine (Br), leading to a greater electronegativity difference between sulfur and chlorine (Cl) compared to bromine and chlorine. This larger electronegativity difference results in a more polar bond.
The bond between Br-I is more polar than the bond between Br-Cl. This is because iodine is less electronegative than chlorine, resulting in a larger difference in electronegativity between the two atoms in the bond. Therefore, the Br-I bond will exhibit stronger polarity.
F CL Br I At
Ag, Hg, Pb
They are both strong acids/weak bases however Br is the stronger acid and by that definition the weaker base.