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lone pair has more electrons than bond pair

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Why the lone pair lone pair repulsion is maximum?

Lone pair-lone pair repulsion is maximum because both lone pairs are localized around the same atom, leading to a strong electrostatic repulsion due to their negative charge densities being in close proximity. This results in a greater repulsion compared to other interactions like lone pair-bonding pair or bonding pair-bonding pair repulsions.


How long does a lone pair distort the molecular shape?

A lone pair can significantly distort the molecular shape, particularly in molecules with a central atom that has both bonding pairs and lone pairs of electrons. The presence of a lone pair generally leads to a repulsion that is stronger than that of bonding pairs, causing bond angles to be altered. This distortion is often observed in geometries like trigonal pyramidal or bent, compared to their idealized counterparts. The extent of distortion depends on the number and arrangement of the lone pairs relative to the bonding pairs.


How does electron repulsion determine molecule shape?

Because they push the bonding pairs down. For example in a water molecule, it has 2 lone pairs which push the 2 bonding pairs down to form a V-shaped molecule. Hope this helps


How does the electron repulse determine molecular shape?

Electron repulsion influences molecular shape through the Valence Shell Electron Pair Repulsion (VSEPR) theory, which posits that electron pairs around a central atom will arrange themselves to minimize repulsion. This arrangement leads to specific geometries based on the number of bonding and lone pairs. For instance, a molecule with four electron pairs will adopt a tetrahedral shape, while one with three bonding pairs and one lone pair will take on a trigonal pyramidal shape. Ultimately, the repulsion between these electron pairs dictates the overall spatial arrangement of the atoms in the molecule.


Why bond angle in H2S is lower then H2O?

The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory

Related Questions

Why the lone pair lone pair repulsion is maximum?

Lone pair-lone pair repulsion is maximum because both lone pairs are localized around the same atom, leading to a strong electrostatic repulsion due to their negative charge densities being in close proximity. This results in a greater repulsion compared to other interactions like lone pair-bonding pair or bonding pair-bonding pair repulsions.


What has the strongest repulsion bonding pairs or lone pairs?

Lone pairs typically have the greater repulsion because lone pairs want to be as far apart from one another as possible, even more so than bonding pairs. This is because the lone pairs consist of free-moving electrons.


Why does the repulsion between lone pairs are stronger than the repulsion between bonding pairs or between one bonding pair and a lone pair?

Repulsion between lone pairs is stronger because they are closer to the nucleus and repel more strongly than bonding pairs. Lone pairs have less electron-cloud shielding compared to bonding pairs, resulting in increased repulsion. This leads to lone pairs pushing each other apart more forcefully than bonding pairs do.


How does a lone pair distort molecular shape?

A lone pair of electrons takes up space despite being very small. Lone pairs have a greater repulsive effect than bonding pairs. This is because there are already other forces needing to be taken into consideration with bond pairs. So to summarize: Lone pair-lone pair repulsion > lone pair-bond pair repulsion > bond pair-bond pair repulsion. This makes the molecular geometry different.


How does a lone pair distort a molecular pair?

A lone pair of electrons takes up space despite being very small. Lone pairs have a greater repulsive effect than bonding pairs. This is because there are already other forces needing to be taken into consideration with bond pairs. So to summarize: Lone pair-lone pair repulsion > lone pair-bond pair repulsion > bond pair-bond pair repulsion. This makes the molecular geometry different.


How does lone pairs distort the molecular shape?

A lone pair of electrons takes up space despite being very small. Lone pairs have a greater repulsive effect than bonding pairs. This is because there are already other forces needing to be taken into consideration with bond pairs. So to summarize: Lone pair-lone pair repulsion > lone pair-bond pair repulsion > bond pair-bond pair repulsion. This makes the molecular geometry different.


How does a lone pair distort the molecular shape?

A lone pair of electrons takes up space despite being very small. Lone pairs have a greater repulsive effect than bonding pairs. This is because there are already other forces needing to be taken into consideration with bond pairs. So to summarize: Lone pair-lone pair repulsion > lone pair-bond pair repulsion > bond pair-bond pair repulsion. This makes the molecular geometry different.


What is the change in bond angle down a group when central atom has lone pair?

there is repulsion between lone pair and bond pair for example in water molecule oxygen has lone pair which repells the bond pair due to this bond angle decreases simply ddue to repulsion btween lone pair to lone pair or lone pair to bond pair angle varies


What is responsible for the bent nature of NH3?

There are 3 bonding pairs of electrons N - H and one lone pair . The repulsion forces between lone pair -lone pair is > lone pair -bond pair > bond pair - bond pair. So the lone pair causes distortion from a perfect tetrahedron


Why is the water bond angle 104.5 less than the CH4 bond angle 109.5?

in water there are two bond pairs and two lone pairs where as in CH4 there are are four bond pairs nad no lone pair. in ch4 there is only bond pair to bond pair repulsion but in water there are three types of repulsions, lone to lone (greatest repulsion), lone to bond ( lesser repulsion ) and bond to bond ( the least repulsion) , therefore due to the presence of two lone pairs in water the bond pairs are repelled with greater force and they get compressed, reducing the ideal bond angle from 109.5 to 104.5 on the other hand, ch4 has only bond pairs and they dont repel each other that strongly so its angle is greater n its 109.5..


What are repelled in the VSEPR theory?

Electron pairs


How does electron repulsion determine molecule shape?

Because they push the bonding pairs down. For example in a water molecule, it has 2 lone pairs which push the 2 bonding pairs down to form a V-shaped molecule. Hope this helps