Usually when voltage increases current increases too, but when it happens that current decreases when voltage increase to minimize lose of power.
Total power = IV
Power loss = I * V(across wire) = I^2 R = (Power / V)^2 R
V = potential difference across the wire which is much smaller (you hope) than the total potential difference between the wire and ground.
So you lose less power using a very high voltage and a very low current for transmission and then transforming to the voltage you need at the point of delivery.
The terminal voltage of a self-excited shunt generator decreases with an increase in load due to an increase in voltage drop across the internal resistance of the generator. As the load current increases, the drop across the internal resistance also increases, reducing the output voltage available at the terminals. This effect is known as voltage regulation and is a common characteristic of self-excited shunt generators.
This question makes no sense as written. However, maybe it will help to know that for a given load if you increase voltage the current increases proportionally and if you decrease the voltage the current decreases proportionally. Ohm's Law says Voltage = Current x Resistance.
The resistance of the new bulb is likely higher than the previous bulb. Increasing resistance in a series circuit decreases current flow. When resistance increases, less current can flow through the circuit, resulting in a decrease in current.
In a series generator, the voltage output is directly affected by the load. As the load increases, the voltage output decreases due to increased voltage drops across the internal resistance of the generator. Conversely, reducing the load will result in an increase in the voltage output.
The electrical potential energy increases as the voltage is increased. It further excites the filament in the bulb more than a lessor voltage would. Using good old ohm's law (Voltage = Current x Resistance), a larger voltage applied to a bulb at the same resistance increases the current proportionally and larger currents has the effect to cause higher temps in conductors
Ohm's Law says that Voltage = Current x Resistance (Load). Therefore Current = Voltage / Resistance and as resistance decreases current increases and as resistance increases current decreases.
TRANSFORMER
Current increases if the voltage remains constant.
capacitors
Ohm's Law Voltage = Current x Resistance. So for a fixed voltage as R decreases then current increases proportionally.
Current and voltage are directly proportional according to Ohm's Law. This means that as voltage increases, current increases proportionally, and as voltage decreases, current decreases proportionally. Mathematically, this relationship is expressed as I = V/R, where I is current, V is voltage, and R is resistance.
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
Voltage is directly proportional to current, meaning that as voltage increases, current also increases and vice versa, as per Ohm's Law. However, voltage is inversely proportional to resistance, meaning that as voltage increases, resistance decreases and vice versa.
Ohm's law says the opposite.
If resistance increases and voltage stays the same, then current decreases. Ohm's Law: Current equals Voltage divided by Resistance.
Ohm's Law states that the current passing through a conductor between two points is directly proportional to the voltage across the two points. This means that as voltage increases, current increases, and as resistance increases, current decreases.