The pressure of a gas at constant volume can fall due to a decrease in temperature, as described by Gay-Lussac's law. When the temperature of the gas decreases, the kinetic energy of the gas molecules reduces, leading to fewer collisions with the container walls and consequently lower pressure. Additionally, if the gas is allowed to expand or if there are any leaks in the system, the pressure would also decrease.
Pressure is halved when ONLY volume is doubled (n and T are constant).Remember the General Gas Law:p.V = n.R.T(in which R=general gas constant)
If the pressure is doubled according to the ideal gas equation (PV = nRT), and the other variables remain constant, then the volume would be halved. This is because pressure and volume are inversely proportional when the other variables are constant in an ideal gas.
According to Boyle's Law, if you double the volume of a gas at constant temperature, the pressure is halved. So, the pressure would decrease to 190 mm Hg when the gas sample is expanded to 800 mL.
Using the combined gas law (P1V1/T1 = P2V2/T2), we can calculate the new volume of the oxygen gas sample at 600K. Given P1V1/T1 = P2V2/T2, we have P1 = P2 (pressure is constant), V1 = 150 mL, T1 = 300K, and T2 = 600K. Plugging in these values, we get V2 = (P1 * V1 * T2) / (T1) = (1 * 150 * 600) / (300) = 300 mL. So, the new volume of the oxygen gas sample at 600K would be 300 milliliters.
No, the density of water remains constant regardless of the sample size, as long as the temperature and pressure are the same. Density is defined as mass per unit volume, so both a 10 mL and a 5 mL sample of water will have the same density, which is approximately 1 g/mL at room temperature. Thus, the density does not change with the volume of the sample.
According to Boyle's Law, at constant temperature, the pressure and volume of a gas are inversely proportional. So, if the pressure is tripled, the volume would become one-third of the original volume. Therefore, the new volume would be 0.33 L.
Volume & pressure are inversely proportionate, if temperature stays constant volume would decrease at a factor proporionate to the increase in pressure.
If the temperature of the gas is decreasing, then in order to maintain constant pressure, you would have to compress it in volume.
Using the ideal gas law equation, we can calculate the new volume of the gas. At STP, the pressure is 1 atm, which means 50 atm is 50 times greater. So the new volume would be 1.55L / 50 = 0.031L, when the pressure is increased to 50 atm.
Pressure is halved when ONLY volume is doubled (n and T are constant).Remember the General Gas Law:p.V = n.R.T(in which R=general gas constant)
If the pressure is doubled according to the ideal gas equation (PV = nRT), and the other variables remain constant, then the volume would be halved. This is because pressure and volume are inversely proportional when the other variables are constant in an ideal gas.
Using the ideal gas law (PV = nRT), since the temperature is constant, the relationship between pressure and volume is inversely proportional. Therefore, if the pressure doubles from 75kPa to 150kPa, the volume will halve. The new volume would be 87.5 mL.
When the temperature of a gas is constant and the volume decreases, the pressure of the gas increases. This relationship is described by Boyle's Law, which states that pressure and volume are inversely proportional when temperature is held constant.
According to Boyle's Law, if you double the volume of a gas at constant temperature, the pressure is halved. So, the pressure would decrease to 190 mm Hg when the gas sample is expanded to 800 mL.
If the pressure of the ideal gas is kept constant and the volume is desired to double, the temperature must also double according to the ideal gas law: V2 = 2V1 = (2/1)×V1 when T2 = 2T1. This relationship results from the formula PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature.
A sample of Ar gas occupies a volume of 1.2 L at 125°C and a pressure of 1.0 atm. Determine the temperature, in degrees Celsius, at which the volume of the gas would be 1.0 L at the same pressure.
The Ideal Gas Law states that PV=nRT, where P=pressure, V=volume, n=number of moles of gas, R=the relativity constant, and T=temp in Kelvin. According to this law, volume (V) varies as V=(nRT)/P. Using this, we can determine that the volume would normally increase with an increase in the number of moles and/or an increase in the temperature and/or a decrease in pressure. Therefore, we can logically determine that the volume of a gas would decrease in the instance of increasing temperature if either the number of moles of gas was decreased or the pressure was increased (to an extent where the level of volume increase by temperature change has been overcome.)