A sample of Ar gas occupies a volume of 1.2 L at 125°C and a pressure of 1.0 atm. Determine the temperature, in degrees Celsius, at which the volume of the gas would be 1.0 L at the same pressure.
The temperature at which an ideal gas occupies zero pressure is called absolute zero. It is defined as 0 Kelvin or -273.15 degrees Celsius. At this temperature, the particles in the gas have minimal kinetic energy and do not exert any pressure.
The answer is 1,83 moles.
A fixed quantity of gas at a constant pressure exhibits a temperature of 27 degrees Celsius and occupies a volume of 10.0 L. Use Charles's law to calculate: the temperature of the gas in degrees Celsius in atmospheres if the volume is increased to 16.0 L
If the gas is ideal, or nearly so, it must be at or nearly at standard temperature and pressure.
1 mole of gas at STP occupies 22.4 liters.
Rigid container holds hydrogen gas at a pressure of 3.0 atmospheres and a temperature of 2 degrees Celsius. The pressure if the temperature is raised to 10 degrees Celsius will be 15 atmospheres based on the law of pressure for gas.
Standard temperature and pressure (STP) for oxygen is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals). At STP, one mole of oxygen gas occupies a volume of 22.4 liters.
You cannot. kiloPascals is a measure of PRESSURE. Celsius is a measure of TEMPERATURE.
At STP(Standard Temperature and pressure), the temperature is zero degrees Celsius(273 Kelvin) and the pressure is 1 atmosphere. At RTP(Room temperature and pressure), the temperature is 25 degrees Celsius(298 Kelvin) and the pressure is 1 atmosphere.
A gas occupies 40.0 L at -123 Celsius. It occupies 80 L of volume at 27 degrees Celsius.
To determine the pressure of the gas when the temperature rises to 87 degrees Celsius, you would need additional information such as the initial pressure, volume, and type of gas. Use the ideal gas law equation (PV = nRT) to calculate the final pressure. Make sure to convert the temperature to Kelvin (87°C + 273 = 360 K) before solving the equation.
The temperature of the water is 100 degrees celsius.