If the gas is ideal, or nearly so, it must be at or nearly at standard temperature and pressure.
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies approximately 22.4 liters. Therefore, 1 mole of O₂ occupies 22.4 liters, and 1 mole of O₃ also occupies 22.4 liters, as it is also a gas under these conditions. Thus, the volume ratio of 1 mole of O₂ to 1 mole of O₃ is 1:1.
It occupies 22.4 L
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
One mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, one mole of helium would also occupy 22.4 liters at STP.
This is the molar volume of an ideal gas at a given temperature and pressure.
1 mole of gas at STP occupies 22.4 liters.
One mole of any gas at STP occupies 22.4 liters. Therefore, one mole of oxygen gas at STP also occupies 22.4 liters.
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
1 mole of gas at STP occupies 22.4 liters.
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
It occupies 22.4 L
Standard molar volume of the substance.
By knowing the no of moles in a gas. Because , in any gas one mole of gas occupies Avagadro number of molecules.
1 mole of gas at STP occupies 22.4 liters.
1 mole of gas at STP occupies 22.4 liters.
It occupies 22.4 L