Check the voltages on the other receptacles in the home. If you find other lower voltages go back and shut that breaker off. Go through out the house shutting off the breakers that have low voltage on them. If other ones are lower see if you can establish if the voltage drop is on the same bus breakers. These will be every alternate breaker. If the breakers that you shut off are every other breaker then the problem is with the incoming utility supply. Give them a call and get them to read the voltage at the meter base. If you can not find any other low voltages in the home then shut the breaker off to that circuit and change the receptacle out for a new one. If the voltage is still low after replacing the receptacle, it could be the breaker that is feeding that circuit.
The voltage drop across the wiring in the wall is calculated using Ohm's Law: V = I * R, where V is the voltage drop, I is the current, and R is the resistance. Plugging in the values, V = 10 A * 0.12 ohms = 1.2 V. Therefore, the voltage drop across the wiring in the wall is 1.2 V.
120 Volts and 115 Volts refer to the same thing in the US. Residential electricity is provided at 120 Volts from the utility. High current devices such as motors are often rated at less than the supplied voltage (such as 115 Volts) because it is expected that there is a small amount of voltage drop in the circuit feeding them. The National Electric Code allows a 5% drop in voltage from the electric service so a 5 Volt drop from 120 Volts is OK.
Voltage drop is typically measured in units of volts (V). It is a way to quantify the loss of voltage as electrical current flows through a circuit due to resistance. Voltage drop can be calculated by measuring the difference in voltage between two points in the circuit.
Actual voltage would be 240V. 4 AWG copper is capable of carrying 50A. At 200 ft, with a 50A load, voltage drop would be about 6V, which is within the acceptable 3% voltage drop for a branch circuit.
It depends on the current flowing in the wire. V=IR. The wires have resistance (easily calculated, approx. .32 ohms for 200 feet of wire (100 feet out and back)). If 20 amps are flowing in the circuit the the voltage drop is about 6.4 volts. That means you're converting electricity to heat in the wires at a rate of about 130 Watts. If less current is flowing then there is a smaller voltage drop in the wire.
The voltage drop across the wiring in the wall is calculated using Ohm's Law: V = I * R, where V is the voltage drop, I is the current, and R is the resistance. Plugging in the values, V = 10 A * 0.12 ohms = 1.2 V. Therefore, the voltage drop across the wiring in the wall is 1.2 V.
The voltage would 9V minus any drop in the battery.
voltage drop is zero bcz in open ckt current will be zero
Zero, or very close to it. If there is a large neutral current flowing, voltage drop on the neutral leg could cause a volt or so to read between the two. If you read full line voltage, the outlet is wired wrong!
the voltage drop means whenever the conductor passing through the supply voltage, according to the resistivity property to reduces the some amount of voltage that drop is known as voltage drop for example the resistance is used to drop the voltage to the circuit.............................................
Voltage drop depends on the size & length of the wire and the wattage of the bulbs. If they make an LED replacement bulb , you would hardly notice the voltage drop.
Voltage drop is caused by circuit resistance
120 Volts and 115 Volts refer to the same thing in the US. Residential electricity is provided at 120 Volts from the utility. High current devices such as motors are often rated at less than the supplied voltage (such as 115 Volts) because it is expected that there is a small amount of voltage drop in the circuit feeding them. The National Electric Code allows a 5% drop in voltage from the electric service so a 5 Volt drop from 120 Volts is OK.
High resistance on the feeder to the load will cause voltage drop at the load end of the circuit. If this is happening, do the calculations for voltage drop, using the amperage of the load, voltage of the load, the size of the wire feeding the load and the distance from the distribution panel to the load.
The voltage drop should be as close to zero as would be readable by a typical volt meter. If it is measurable you likely have a problem with corrosion or oxidation in switch that is increasing resistance. If you can measure a voltage drop across a closed switch contact, replace the switch. Or the switch is open, try flipping the switch!
The voltage drop in a line can be decreased by
Voltage drop is caused by resistance. From the equation V=IR the voltage across that resistance can be calculated. For a uniform conductor the resistance is linear with the length R=kx where k is in ohms per foot. For a given current, the voltage drop V=Ikx so the voltage drop per foot is Ik. Voltage drop per foot can be measured, allowing a calculation of voltage drop for very long lengths of conductor such as power transmission lines. This is a reasonable approximation as long as the total voltage drop in transmission is small relative to the supply voltage. If the voltage drop is large, the current will be limited by the total resistance. This implies that long distance transmission lines should be high voltage, because 1 megawatt at 10,000 volts requires 100 amps, while at 100,000 volts it only requires 10 amps. The voltage drop per foot for the same conductor would be 10 times as large at 10 times the current, and the power loss (I*IR) would be 100 times as large. For alternating current, inductance can be a factor; this implies that relatively low frequency would be preferred.