Suppose the atoms in a receding cloud have two energy levels separated by an energy corresponding o 4863 Angstroms. The observer will see emissiom at a greater or less wavelength.
probably wavelength
Atomic absorption is more sensitive to atomic emission when the excitation potential is greater than 3.5eV.
The shorter the wavelength of visible light, the higher the frequency and the greater the energy of the photons.
The meaning of a high frequency wave is a shorter wavelength.For electromagnetic waves in general (including light):* At greater frequencies, you get shorter wavelengths.* At greater frequencies, you get more energy per photon.
The resolving power of a microscope is inversely proportional to the wavelength of light being used. This means that as the wavelength of light decreases, the resolving power of the microscope increases. Shorter wavelengths can resolve smaller details, allowing for higher magnification and clearer images.
A radio wave has a greater wavelength compared to a visible light wave.
probably wavelength
yes
True. Waves with a greater wavelength will have a longer distance between each wave crest compared to waves with a shorter wavelength.
If a wave travels at a constant speed, the greater its wavelength, the lower its frequency. This is because frequency and wavelength are inversely proportional in a wave, according to the formula: speed = frequency x wavelength.
Good luck, Greater wavelength=TV. frequency= the number of wave cycles(peak, trough, peak) per time unit. The higher the frequency, the more times the wave cycles, and the shorter the wavelength. Greater Energy=Ultraviolet lamp. By Placks constant, E(energy) =h(planck's constant which is the energy of a photon divided by it's frequency) / f(the frequency of that photon). Planck's constant is almost irrelevant, so the greater the frequency, the greater the energy. Greater frequency=Ultraviolet lamp. Planck's constant and light spectrum. Greater Momentum= Ultraviolet lamp. Electron diffraction, Wavelength=h(planck's constant) / momentum. rearrange it as M=h/W. The greater the wavelength, the smaller the momentum, and visa versa.
frequency. This is because frequency and wavelength are inversely proportional in a wave - as wavelength increases, frequency decreases.
Energy is inversely proportional to wavelength: the shorter the wavelength (X-rays, gamma rays) the greater the energy.
The wave with the greater frequency has the greatest wave speed. Wave speed is directly proportional to frequency and wavelength, so if two waves have the same wavelength, the wave with the higher frequency will have the greater speed.
Yes definitely. Reciprocal of wavelength is proportional to frequency as lambda = v /frequency. v - the speed of the wave. The frequency has to be greater than some minimum value known to be the threshold frequency. As frequency increases then kinetic energy of the photo electron also increases. If the frequency of the incident photon is less than the threshold and however higher the intensity, there is no chance of ejection of photo electron right from the surface of the substance. So no photo electric emission is possible.
The wavelength is greater than 300E6/300E9 = 1 mm and the frequency is less than about 300 Gigacycles.
Indigo light has a greater wavelength than blue light. This is because indigo light falls between blue and violet on the electromagnetic spectrum, and wavelengths decrease from red to violet. Hence, indigo light has a longer wavelength than blue light, making it closer to violet light in terms of wavelength.