0
This would be the issue with John Cippolina from The Quicksilver Messenger Service,I believe.John has passed away a few years back,so I would imagine it`s worth a few George Washington`s these days.I have that issue plus many more for the 70s and 80`s for sale if anyone is interested.gbkeeler@comcast.net
What else can I help you with?
What is the value of the variable num1 after executing this pseudocode?
To determine the value of the variable num1 after executing the pseudocode, I would need to see the specific pseudocode you are referring to. Please provide the pseudocode so I can analyze it and give you the correct value of num1.
How to Write a psuedocode algorithm to read in three numbers and print the highest and lowest number?
read num1 read num2 sum = num1 num2 print highest value
C program to find addition of two long integer numbers?
#include<stdio.h> main() { long int num1, num2; long int sum=0; printf("Enter Value="); scanf("%ld", &num1); printf("Enter Value="); scanf("%ld", &num2); sum=num1+num2; printf("The Result is=%ld", sum); }
How do you determine the largest of 3 numbersi in pseudocode?
To determine the largest of three numbers in pseudocode, you can use the following logic: if (num1 >= num2) and (num1 >= num3) then largest = num1 else if (num2 >= num1) and (num2 >= num3) then largest = num2 else largest = num3 This structure checks each number against the others and assigns the largest value to the variable largest.
How do you divide two numbers using c program?
int num1 = 5; int num2 = 5; printf ("%d/%d=%d\n", num1, num2, num1/num2); and if you want to enter during the program then int num1; int num2; printf ("what is the first number?"); scanf ("%d", &num1); printf ("what is the second number?"); scanf ("%d", &num2); printf ("%d/%d=%d\n", num1, num2, num1/num2); i hope this helped
C program to find the LCM of two numbers?
#include <stdio.h>int main(){ int num1, num2, max; printf("Enter two positive integers: "); scanf("%d %d", &num1, &num2); max=(num1>num2) ? num1 : num2; while(1) { if(max%num1==0 && max%num2==0) { printf("LCM of %d and %d is %d", num1, num2,max); break; } ++max; } return 0;}
In program c accept numbers num1 and num2 find the sum of all add numbers between the two numbers entered?
#include<stdio.h> main() { int num1; int num2; int a; printf("Enter any two numbers :"); scanf("%d%d",&num1,&num2); for(a=num1;num1<=num2;a++) { if ( a % 2 == 1); { printf("%d",a); } } getch(); }
Program to find greatest of two numbersin c?
if num1>num2 return num1 else return num2
Which is the code to multiply a number num1 by 2 using bitwise operator in c?
num1 <<= 1; /* shift left */
What is the function key to execute Qbasic program?
QBASIC operators are listed as follows.../along with some example QBASIC code... ->LOGICAL OPERATORS AND OR NOT EXAMPLE QBASIC CODE:- A=1 B=1 IF (A AND B) THEN PRINT "Result: True" ELSE PRINT "Result: False" ...output... Result: True A=1 B=2 IF (A AND B) THEN PRINT "Result: True" ELSE PRINT "Result: False" ...output... Result: False -> MATHEMATICAL OPERATORS + plus - minus * multiply / divide MOD division remainder ^ raise to the power EXAMPLE QBASIC CODE:- num1=4 num2=2 PRINT num1 + num2 PRINT num1 - num2 PRINT num1 * num2 PRINT num1 / num2 PRINT num1 MOD num2 PRINT num1 ^ num2 ...output... 6 2 8 2 0 16 -> COMPARISON OPERATORS = equals > greater than < lesser than >= greater than/or, equals <= lesser than/or, equals <> not EXAMPLE QBASIC CODE:- num1 = 6 num2 = 8 IF num1 = num2 THEN PRINT "Equal to" IF num1 > num2 THEN PRINT "Greater than" IF num1 < num2 THEN PRINT "Lesser than" IF num1 >= num2 THEN PRINT "Greater than/or, equal to" IF num1 <= num2 THEN PRINT "Lesser than/or, equal to" IF num1 <> num2 THEN PRINT "NOT equal" ...output... Lesser than Lesser than/or, equal to NOT equal
How do you create a program that will add 2 numbers?
first you make 3 integer variables. lets called them sum1, num1 and num2 then you get user imput that will assign num1 and num2 with values or make a statment giving them valvues such as num1=5 num2=3 then you make a statement that assigns sum1 a valvue, sum1=num1 + num2 Thats it.
How do you do an alternate numbers in c plus plus?
If I'm understanding correctly, you want to alternate between two numbers back and forth? If so, try something like this: /* num1 is the number to be alternated and alt is the amount of times do so */ int num1 = 1; int alt; /* Get number of times to alternate */ cout << "Enter number of times to alternate: "; cin >> alt; /* Perform alternation and cout result each time */ for (int i = 0; i < alt; i++) { num1 *= -1; // in this case, alternating positive/negative cout << num1 << endl; } Note that you can change the "num1 *= -1" to whatever you need. For example, to alternate between 50 and 25, you would put /* Starting with 50, then alternating to 25 for the first cout */ num1 = 50; /* On odd times through (1,3,5), ADD 25; On even times through (0,2,4...etc) SUBTRACT 25 */ if ( (i % 2) == 1) { num1 += 25; } else { num1 -= 25; }
