Let's represent the number of birds as 'b' and the number of beasts as 'c'. Each bird has one head and two feet, while each beast has one head and four feet. Given that the total number of heads is 36 and the total number of feet is 100, we can create two equations: b + c = 36 (total number of heads) and 2b + 4c = 100 (total number of feet). Solving these equations simultaneously, we find that there are 22 birds and 14 beasts on the farm.
los pies = feet
smelly feet
feet - pieds foot - pied :)
A tape measure has a feet, inches and CM measurement.
Pies is the Spanish word for "feet".
Birds and beasts have one head each. So totally there are 43 birds & beasts. Let number of birds = x number of beasts = (43-x) Birds have 2 feet and beasts have 4 feet. Total feet = 2 * no of birds + 4 * no of beasts = 2 * x + 4 * (43 -x) = 172 - 2*x (on simplification) = 120 (given) 172 - 2*x = 120 2*x = 172 - 120 = 52 x = 52/2 = 26 number of birds = x = 26 number of beasts = 43 -x = 43 -26 = 17 (check: 26 + 17 = 43 ; 26*2 + 17*4 = 52 + 68 = 120)
There are 13 birds in the cage.
Ok, so we know altogether there are 30 animals(all animals have heads right?). Sooo... I make it, 20 land beasts and 10 birds. Sorry if its wrong! :> - that's meant to be a bird by the way.
Ships, beasts of burden, feet.
no flowing of blood in the feet of birds
Assuming the dogs have four feet and birds two, you need 15 dogs (60 feet) and 1 bird (2 feet) giving a total of 16 birds and dogs and 62 feet. None. Dogs have paws, not feet. Also, birds have claws, not feet.
The average height of the Easter Island heads is around 13 feet, with some reaching up to 33 feet tall. The width of the heads ranges from about 6 to 13 feet.
Mainly webbed feet are seen on swimming birds
You can tell that birds naturally clench their feet because their feet are rolled up in a ball
Here's a Perl script that will answer the problem for any number of heads and feet. sub how_many { print "Number of heads: "; chomp($h = ); print "Number of feet: ";chomp($f = ); $p = $h; $c = 0; while (($p*4 + $c*2) != $f) { $p--; $c++; } } &how_many; print "There are $p pigs and $c chickens.\n"; print "They have $h heads and $f feet.\n"; Number of heads: 27 Number of feet: 78 There are 12 pigs and 15 chickens. They have 27 heads and 78 feet.
Aliens.
Hot Heads and Cold Feet - 1915 was released on: USA: 4 December 1915