Medium-large probably, though I'm no expert
You mean a volume of 30 ml and mass of 579 g. Its s density = mass/volume = 579/30 = 19.3 g/ml which is very heavy. It could be several choices, but GOLD is that density...
19.3
150ml is 3/5 of 250ml - a quarter of a litre is that what you mean?
If you mean cc as in from a motorbike it stands for centimetres cubed. It is a unit of Volume. 1 cc = 1 ml
Medium-large probably, though I'm no expert
To determine if the ring is pure gold, we can calculate its density using the formula Density = Mass/Volume. The calculated density of the ring is approximately 16.9 g/ml, which is lower than the density of pure gold (19.3 g/ml). Therefore, the ring is not made of pure gold, as its density does not match the density of pure gold.
No. Coke is mostly water which has a density of 1 g/ml. Gold alloys have a density of around 19 g/cm3.
You find a ring with a mass of 107 g. You fill a graduated cylinder up with 10 mL of water and put the ring into the cylinder. The water rises up to the 15 mL mark. What is the ring made out of A. Marble 2.56 B. Diamond 3.52 C. Gold 19.32 D. Platinum 21.4 Any guesses?
The volume of the ring is the difference in water levels, which is 0.2 mL (4.2 mL - 4.0 mL). Since the density of platinum is 21 g/cm3, the mass of the ring can be calculated as 21 g/cm3 * 0.2 mL = 4.2 grams.
2 mL
79,2 ml
its stamped on the case in ml by the fill hole
The volume of the gold nugget can be calculated by subtracting the final volume (225 ml) from the initial volume (80 ml) of water in the graduated cylinder. Therefore, the volume of the gold nugget is 145 ml.
The volume of gold displacing the water can be found using the density formula: density = mass/volume. Rearranging the formula to solve for volume, volume = mass/density. Plugging in the values given, volume = 100 grams / 19.3 grams per ml = 5.18 ml. So, the gold should displace 5.18 ml of water.
The volume of the gold nugget can be calculated by finding the difference in volume before and after adding the nugget. The volume of the gold nugget is 225 mL (final volume) - 85 mL (initial volume) = 140 mL.
The volume of the nugget of gold is 15 ml because the increase in volume from 250 ml to 265 ml is the volume displaced by the nugget of gold.