of incline is θ=30⁰. Coefficient of friction of the incline is, μk=0.5. A
horizontal force, F, is acting on the block as shown in the figure. (Assume
g=10 m/s and do not forget that the direction is downward!!) (Note: You
don’t have to use unit vectors. Mentioning the sign convention correctly for
all forces is enough for the answer.)
a) Determine the magnitude of the force F.
b) Determine the normal force exerted by the incline surface to the block
s=s^i+v^i*t+ 1/2 at^2
As block is starting from rest so its s^i and v^i will be zero,,
now eqn comes to s=1/2 at^2
..
by putting the values u can easiily find the answer.!
displacement = (avg velocity /2) * t
2m = (avg velocity /2) * 1.5 sec
avg velocity = 2.67m/s
v/t= a
2.67/1.5s = 1.78m/s2
On a speed versus time graph, acceleration is represented by the line on the graph. If acceleration is constant, the line cuts through equally between the axis and starts from the zero point.
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
It will take a half second.
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
You have acceleration any time a velocity changes - like when an object falls down due to gravity, when a car starts or stops, when you start moving or stop moving, etc.
mass = 1.9 kg distance (s) = 0.825 metres time (t) = 0.4 seconds initial velocity (u) = 0 metres/sec to find acceleration (a) shuffle s = ( u * t ) + ( 0.5 * a * t^2 ) to isolate a a = s - ( u * t ) / ( 0.5 * t^2 ) a = ( 0.825-0 ) / ( 0.5 * 0.16 ) a = 0.825 / 0.08 a = 10.3125 ( m / s ) / s force required to give 1.9 kg mass an acceleration of 10.3125 ( m / s ) / s f = m * a f = 1.9 * 10.3125 f = 19.59 newtons
This is a tough question. There's so much information given that it's difficult to dig past the useless stuff and find our way to the info we actually need. Turns out we don't need the mass of the block or the angle of the incline. We can do just fine with the acceleration and distance. Average velocity = 1/2 (Vinitial + Vfinal) = 1/2 Vfinal Distance = (average velocity) times (time) time = Distance / (average velocity) = 2 x distance / Vfinal = 4 / Vfinal Distance = 1/2 a t2 = 1/2 (0.5) (4/Vfinal)2 2 = 1/4 x 16 x (1/V2final) ===> 2 V2final = 4 ===> V2final = 2 Vfinal = sqrt(2) meters/sec
Substitute teachers, or for elementary schools Slides
I would say positive, as she starts the incline of the hill, she has to pedel harder and harder, whilst doing this she would be slowing down, so yeah, positive
The incline plane is the simple machine that starts with an I. The other five are wheel and axle, wedge, lever, screw and pulley.
Inclined plane. One of the six; screw, wedge, incline plane, pulley, wheel and axle, and lever.
32
On a speed versus time graph, acceleration is represented by the line on the graph. If acceleration is constant, the line cuts through equally between the axis and starts from the zero point.
may be octobe
The acceleration zone is the portion of the runup area for the pole vault, long jump, etc. where the athlete starts his run and gets up to speed.
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
It will take a half second.