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How do i calculate the new conductance of a wire if the conductance of the wire is 100 S and the area of the wire is increased by 23 and the length is reduced by the same amount?
To calculate the new conductance, simply multiply the initial conductance by the change in area: 100 S * 23 = 2300 S. Since the length of the wire is reduced by the same amount as the area is increased, the overall conductance remains the same.
If a wire of resistivity is stretched to thrice its initial length what will be its new resistivity?
The new resistivity of the wire will remain the same, as resistivity is a material property and is independent of the dimensions of the wire. The resistance of the wire will increase because of the increase in length.
What happens to the current in a wire as its diameter decreases?
As the diameter of a wire decreases, the current-carrying capacity also decreases due to increased resistance. This can lead to overheating of the wire and potential failure if the current exceeds the wire's new lower capacity. It is important to properly size wires to handle the intended current to prevent safety hazards.
What is the internal resistance of a new D battery with an emf of 1.5 V and a wire of negligible resistance is connected between the terminals of the battery a current of 27 A is produced?
"In short, it is 0.055555555555555555555555555555556OhmsYou can use ohms law to calculate this.You will use the formula: Resistance Equals Voltage Divided by Current.It is written: R=V/ISo use the numbers you provided, and the formula above.1.5 / 27 = 0.055555555555555555555555555555556"I dispute this answer. emf = I(R+r) is the actual equation u need. From this equation, u will find that V = emf - Ir. Ohm's law is not applicable for this situation. However I do think you will need a voltage to find the internal resistance.
Is the stopping voltage doubled or more than doubled if frequency of lightwave is doubled under the condition where intensity is constant?
More than doubled. The stopping voltage is the photon energy minus the work function: hv - W Doubling the photon energy creates a new stopping voltage of: 2 hv - W > 2 (hv - W)
If the side of the square is doubled will the new area would be doubled?
the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...
When two terminals of 4.5 Voltage battery are connected by 100 meters long wire. the current in the wire is 50mA what will be the current from the battery when the wire is shortened 50 meters?
-- The resistance of the wire is proportional to its length. -- When the length is reduced by 1/2 , the resistance is also reduced by 1/2 . -- Reducing the resistance across the battery by 1/2 causes the current to double. -- The new current is 100 mA. (Assumes zero internal resistance in the battery, and that the 4.5 volts doesn't 'sag'.)
How do i calculate the new conductance of a wire if the conductance of the wire is 100 S and the area of the wire is increased by 23 and the length is reduced by the same amount?
To calculate the new conductance, simply multiply the initial conductance by the change in area: 100 S * 23 = 2300 S. Since the length of the wire is reduced by the same amount as the area is increased, the overall conductance remains the same.
Does the amperage double when you double both the current and the voltage in a circuit?
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
Where does the fabric coated resistance wire attach inside the car if you are converting from points to a HEI system and need to replace resistance wire with 12 gauge stranded wire?
eliminate the resistor wire all together but you want to run a new larger 12 gauge wire into the same circuit , in order to do that you need to take the fuse box down inside the car and you will see where that resistor wire ties into a big wire in the fusebox, it comes from the ignition switch, you need to tie into that big wire with your 12 gauge wire that you have run from the HEI.
If a wire of resistivity is stretched to thrice its initial length what will be its new resistivity?
The new resistivity of the wire will remain the same, as resistivity is a material property and is independent of the dimensions of the wire. The resistance of the wire will increase because of the increase in length.
On a 77 GMC 350 HEI system with a new pickup coil why can you get no reading for resistance between either wire and ground What could cause this you can get resistance readings everywhere else?
The resistance to ground should be infinite, becouse its an isolated circuit. Any resistance to ground less than infinity would mean there is a short to ground.
What happens to the area of a rectangle if one side is doubled?
Area = length*width new Area = 2 * length * width Area is doubled
What happens to the current in a wire as its diameter decreases?
As the diameter of a wire decreases, the current-carrying capacity also decreases due to increased resistance. This can lead to overheating of the wire and potential failure if the current exceeds the wire's new lower capacity. It is important to properly size wires to handle the intended current to prevent safety hazards.
How does the dimension of a prism change if the dimension of a prism is doubled?
You'd get a new answer.
What can be a solution to resistance to new technology?
The solution to resistance to new technology is the success of that technology.
What happens to resistance when the conductor diameter is increased?
Simply Stated: As electrons move across a wire, they constantly collide with atoms making up a wire. These collisions impede the flow of electrons and are what cause the wire to have resistance. Thus, if the diameter of the wire were larger, it would only make sense that the electrons don't collide as much, therefore creating less resistance due to a larger wire. This is all in accordance to Ohm's law. The resistance is the ratio of the voltage difference across an object to the current that passes through the object due to the existence of the voltage difference. If the object is made of a material that obeys Ohm's Law, then this ratio is constant no matter what the voltage difference is. Consider a copper wire that passes some amount of current, say 1 A, when a voltage difference of 1 V is applied between the ends of the wire. Now consider an identical but separate wire connected across that same 1V potential difference. You would expect that it would also conduct 1 A. Now think of joining those two wires together side by side into one, thicker wire. It is reasonable to expect that this wire should carry 2 A of current if the potential difference across the wires is still 1 V. Thus, the new, thicker wire will have a reduced resistance of 1/2 Ohm compared to the original wire with its resistance of 1 Ohm. Basically, a thicker wire creates additional paths for current to flow through the wire.
