A block is dragged at constant velocity in a straight-line path across a level surface by a force of 6 N what is the force of friction between the block and the surface?

Answer 1

'Constant velocity' means constant speed and direction. If the speed of the block is constant along the level block, then the net force on it in the forward direction must be zero. (It isn't accelerating.) You're pulling it in the forward direction with a force of 6 N. So the force of friction in the opposite direction must also be 6 N, for a total of zero.

Answer 2

variables used here:

f = friction

N = normal force

u = coefficient of friction

Because the box is sliding at a constant rate, we know that the forces are balanced, so the force due to friction must be 6.0 N. We can use the equation f = uN to find the coefficient of friction. We know friction (6.0 N) and the normal forces (18 N), so plugging them in to the equation gives us 6 = u18. Solving for u:

u = 0.33

Answer 3

-- The block is moving at constant speed in a straight line.

-- That means its acceleration is zero.

-- That means the net force on it is zero.

-- That means the force of friction exactly cancels the dragging force.

-- The force of friction is 6N backwards.

Answer 4

To move at a constant velocity, the sum of the forces must be equal to zero. Therefore, the friction must also be 6 N.

Answer 5

6N when we pull an object we have to overcome the force between the surface of the object and the ground. That is why if the surface was lubricated less force would be required.

Answer 6

6n

Answer 7

3.0