Resolve the weight into x and y components
The x component is the force which pushes it down and causes it to acclerate
The y component gives the normal force
Fn=mgcos(A)
Then the force acting sidewards Fx=mgsin(A)
Total force = mgcos(A)-frictional force
Frictional force = umgsin(A)
Therefore total force = mgcos(A)-umgsin(A)=ma
m[gcos(A)-ugsin(A)]=ma
so a=gcos(A)-ugsin(A)
gcos(A)-a=ugsin(A)
u=(gcos(A)-a)/gsin(A)
The normal force between the two objects and the coefficient of friction. Force of friction = normal force x coefficient of friction.
Friction= Normal force* Coefficient of friction
if the static coefficient of friction mew between the tires and the ground is 0.55, then the maximum acceleration of the car will be 0.55g with assumption that there is enough engine power. 0.55g is about 5.4 m/s/s.
A rightward force of 25 N is applied to a 4-kg object to move it across a rough surface with a rightward acceleration of 2.5 m/s/s. Use the diagram to determine the gravitational force, normal force, frictional force, net force, and the coefficient of friction between the object and the surface
This coefficient of static friction is needed to find the frictional force between a body and a surface on which body has to move. If u (mu) is the coefficient of friction then uR gives the frictional force between moving body and surface. There is no unit for coefficient of friction. Here R is reaction which equals to the weight of the body
Friction= Normal force* Coefficient of friction
The normal force between the two objects and the coefficient of friction. Force of friction = normal force x coefficient of friction.
Friction= Normal force* Coefficient of friction
On a flat surface it would be the friction coefficient and the weigh of body.
POMBO
The coefficient of kinetic friction between wool felt and aluminum is about 0.24 to 0.26.
if the static coefficient of friction mew between the tires and the ground is 0.55, then the maximum acceleration of the car will be 0.55g with assumption that there is enough engine power. 0.55g is about 5.4 m/s/s.
Friction between two objects depends on the static coefficient of friction (if the object is currently not moving) and the normal force from the surface, acting in the direction opposite the direction of gravity.
The coefficient of friction is defined as being between two substances, not just one substance.
This coefficient of static friction is needed to find the frictional force between a body and a surface on which body has to move. If u (mu) is the coefficient of friction then uR gives the frictional force between moving body and surface. There is no unit for coefficient of friction. Here R is reaction which equals to the weight of the body
A rightward force of 25 N is applied to a 4-kg object to move it across a rough surface with a rightward acceleration of 2.5 m/s/s. Use the diagram to determine the gravitational force, normal force, frictional force, net force, and the coefficient of friction between the object and the surface
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