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Resolve the weight into x and y components
The x component is the force which pushes it down and causes it to acclerate
The y component gives the normal force
Fn=mgcos(A)

Then the force acting sidewards Fx=mgsin(A)
Total force = mgcos(A)-frictional force
Frictional force = umgsin(A)

Therefore total force = mgcos(A)-umgsin(A)=ma

m[gcos(A)-ugsin(A)]=ma
so a=gcos(A)-ugsin(A)
gcos(A)-a=ugsin(A)
u=(gcos(A)-a)/gsin(A)

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Q: A box slides down a 35 degrees ramp with an acceleration of 1.14 ms2 Determine the coefficient of kinetic friction between the box and the ramp?
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