if the static coefficient of friction mew between the tires and the ground is 0.55, then the maximum acceleration of the car will be 0.55g with assumption that there is enough engine power. 0.55g is about 5.4 m/s/s.
Uk = coefficient of friction
(Uk)(mg)=ma
-you can cancel the mass out
(Uk)g=a
(0.80)(9.8m/s2)=a
7.84m/s2=a
0.83 times the acceleration due to gravity, which is about 9.8 meters per second square.
coefficient of friction = 0.8 tan theta use your calculator : 2nd tan ( 0.8) = 38.66 degrees
It means that the maximum force of friction is greater than the weight of the object.
Frictional force, F = coefficient of friction, u x normal reaction, R Maximum normal reaction = Weight => Maximum frictional force = 62 x 9.8 x 1500 = 911400 N
Really? A coefficient of friction of 7? Unheard of. Probably 0.7 Use F = mv^2 / r where F will be the centripetal force as well as the frictional force, (mu)mg. Solve for v.
The idea here is to: * Write an equation for the centripetal acceleration, using v squared / r. * Calculate the corresponding centripetal force, using Newton's Second Law (multiply the previous point by the mass). * Write an equation for the force of friction. * Equate the two forces, and solve.
coefficient of friction = 0.8 tan theta use your calculator : 2nd tan ( 0.8) = 38.66 degrees
Friction is a force that opposes motion. Maximum friction is the?æ force that must be overcome in order for a body to start moving.?æ Maximum friction is equal to the?æ product of normal force and coefficient of the friction.
Limiting friction is just the maximum static friction force (if you go over that point static friction becomes kinetic friction).Let f = frictional force,c = coefficient of frictionN = Normal forcefmax = cN = limiting frictionAlthough the term coefficient of limiting friction is not really used, I'd assume it would just be "c" (it's a coefficient after all). So they would be the same.If you meant is coefficient of friction the same as limiting friction, than the answer is no. Coefficient of friction is just the "c" in the equation. Limiting friction however is the product of the coefficient and the normal force.
the acceleration is equal to energy that release by the friction that came be electic that travel form somewhere.It proves that maximum acceleration rate.The easy explainationof that is Energy and Velocity are equal to maximum of acceleration
It means that the maximum force of friction is greater than the weight of the object.
friction is the resisting force which oppose the relative motion of two body.cofficient of friction is the ratio of frictional force and normal force of body on surface.thus maximum cofficient of friction defiend as ratio of maximum frictional force or minimum normal force on the surface.
Frictional force, F = coefficient of friction, u x normal reaction, R Maximum normal reaction = Weight => Maximum frictional force = 62 x 9.8 x 1500 = 911400 N
The outer diameter of the friction lining, the inner diameter of the friction lining, the coefficient of friction between the plates, the number of friction plates ( in this case 2), the surface pressure acting on the friction plates
7
In any given case, friction can produce AT MOST a certain amount of friction; if the coefficient of friction is known, this can be calculated as the normal force multiplied by the coefficient of friction.The force necessary to move an object must, of course, be greater than this maximum friction.
The maximum friction that can be generated between two static surfaces in contact with each other. Once a force applied to the two surfaces exceeds the limiting friction, motion will occur. For two dry surfaces, the limiting friction is a product of the normal reaction force and the coefficient of limiting friction.
Really? A coefficient of friction of 7? Unheard of. Probably 0.7 Use F = mv^2 / r where F will be the centripetal force as well as the frictional force, (mu)mg. Solve for v.