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coefficient of friction = 0.8 tan theta

use your calculator : 2nd tan ( 0.8) = 38.66 degrees

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14y ago
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15y ago

COEFFICIENT OF FRICTION = 0.78= tan thita therefore thita =tan-1(0.78) = 40 degree COEFFICIENT OF FRICTION = 0.78= tan thita therefore thita =tan-1(0.78) = 40 degree

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11y ago

.78 g

g being 32 feet/sec squared

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Q: What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.78?
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What is the maximum acceleration a car can undergo on level ground if the static coefficient of friction mew between the tires and the ground is 0.55?

if the static coefficient of friction mew between the tires and the ground is 0.55, then the maximum acceleration of the car will be 0.55g with assumption that there is enough engine power. 0.55g is about 5.4 m/s/s.


What does a coefficient of friction of 1.0 or greater mean?

It means that the maximum force of friction is greater than the weight of the object.


The coefficient of static friction between the tires of a car a dry road is 62 the mass of the car is 1500 kg what maximum force is obtainable?

Frictional force, F = coefficient of friction, u x normal reaction, R Maximum normal reaction = Weight => Maximum frictional force = 62 x 9.8 x 1500 = 911400 N


What is the maximum speed with which a 2500 kg car can round a turn of radius 60 m on a level road if the coefficient of static friction between tire and road is 7?

Really? A coefficient of friction of 7? Unheard of. Probably 0.7 Use F = mv^2 / r where F will be the centripetal force as well as the frictional force, (mu)mg. Solve for v.


What is the maximum speed with which a 1200-kg kg car can round a turn of radius 93.0m on a flat road if the coefficient of static friction between tires and road is 0.45?

The idea here is to: * Write an equation for the centripetal acceleration, using v squared / r. * Calculate the corresponding centripetal force, using Newton's Second Law (multiply the previous point by the mass). * Write an equation for the force of friction. * Equate the two forces, and solve.

Related questions

What is the maximum acceleration a car can undergo on level ground if the static coefficient of friction mew between the tires and the ground is 0.55?

if the static coefficient of friction mew between the tires and the ground is 0.55, then the maximum acceleration of the car will be 0.55g with assumption that there is enough engine power. 0.55g is about 5.4 m/s/s.


What is friction and what is meant by maximum friction?

Friction is a force that opposes motion. Maximum friction is the?æ force that must be overcome in order for a body to start moving.?æ Maximum friction is equal to the?æ product of normal force and coefficient of the friction.


Is coefficient of friction or coefficient of limiting friction are same?

Limiting friction is just the maximum static friction force (if you go over that point static friction becomes kinetic friction).Let f = frictional force,c = coefficient of frictionN = Normal forcefmax = cN = limiting frictionAlthough the term coefficient of limiting friction is not really used, I'd assume it would just be "c" (it's a coefficient after all). So they would be the same.If you meant is coefficient of friction the same as limiting friction, than the answer is no. Coefficient of friction is just the "c" in the equation. Limiting friction however is the product of the coefficient and the normal force.


What is maximum acceleration rate?

the acceleration is equal to energy that release by the friction that came be electic that travel form somewhere.It proves that maximum acceleration rate.The easy explainationof that is Energy and Velocity are equal to maximum of acceleration


What does a coefficient of friction of 1.0 or greater mean?

It means that the maximum force of friction is greater than the weight of the object.


The coefficient of static friction between the tires of a car a dry road is 62 the mass of the car is 1500 kg what maximum force is obtainable?

Frictional force, F = coefficient of friction, u x normal reaction, R Maximum normal reaction = Weight => Maximum frictional force = 62 x 9.8 x 1500 = 911400 N


What is the maximun coefficient of friction between two surfaces?

friction is the resisting force which oppose the relative motion of two body.cofficient of friction is the ratio of frictional force and normal force of body on surface.thus maximum cofficient of friction defiend as ratio of maximum frictional force or minimum normal force on the surface.


The maximum torque transmitted by a single friction clutch plate depends on what factors?

The outer diameter of the friction lining, the inner diameter of the friction lining, the coefficient of friction between the plates, the number of friction plates ( in this case 2), the surface pressure acting on the friction plates


What is the maximum speed with which a 1200- car can round a turn of radius 72 on a flat road if the coefficient of static friction between tires and road is 0.65?

7


How are the force of friction and the force necessary to move an object related?

In any given case, friction can produce AT MOST a certain amount of friction; if the coefficient of friction is known, this can be calculated as the normal force multiplied by the coefficient of friction.The force necessary to move an object must, of course, be greater than this maximum friction.


What is limiting value of friction?

The maximum friction that can be generated between two static surfaces in contact with each other. Once a force applied to the two surfaces exceeds the limiting friction, motion will occur. For two dry surfaces, the limiting friction is a product of the normal reaction force and the coefficient of limiting friction.


What is the maximum speed with which a 2500 kg car can round a turn of radius 60 m on a level road if the coefficient of static friction between tire and road is 7?

Really? A coefficient of friction of 7? Unheard of. Probably 0.7 Use F = mv^2 / r where F will be the centripetal force as well as the frictional force, (mu)mg. Solve for v.