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It means that the maximum force of friction is greater than the weight of the object.
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How much work is done if a 10kg mass is moved 5 meters?
The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.
If you know the coefficient of friction how do you find the maximum velocity to maintain a circular path at a given radius?
say mass(m) = 10 kg, radius(r) = 10 m, say friction coefficient = 0.5 force to break friction = 10 * 0.5 = 5 kgf = say 50 n to find acceleration required to produce this force use f=m*a, shuffle to a = f / m so a = 50 / 10 = 5 (m/s)/s, install in a = v^2 / r, so 5 = v^2 / 10, so 10 * 5 = v^2, so sq. root 50 = v, so v = 7.07 metres / second if friction coefficient and radius remain the same, altering the mass wont alter the velocity at breakaway point
What number is greater 10 to the power 390?
If you mean "greater than", you can raise it to a higher power.
A material has a coefficient of volume expansion of 60×10^-6/degree celsius. What is its coefficient of expansion?
120×10^-6
A 40kg crate is at rest on a level surface if the coefficient of static friction between the crate and the surface is 0.69 what horizontal force is required to get the crate moving?
276 Newtons. Coefficient of static friction is a ratio between the force it takes to budge the object over the normal force (mass times gravity). So: 0.69 = Force / 400 N (40 kg times 10 m/s^2, the force of gravity). Solve for 276 N.
How much work is done if a 10kg mass is moved 5 meters?
The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.
If two numbers are written in scientific notation how can you tell which is the greater number?
The number with the greater coefficient and/or exponent is the greater number. n x 10^E where "n" is the coefficient, and "E" is the exponent. examples: 1.23 x 10^21 > 1.23 x 10^20 1.22 x 10^21 > 1.21 x 10^21 1.22 x 10^21 > 1.22 x 10^-21 see http://www.fordhamprep.org/gcurran/sho/sho/lessons/lesson25.htm for reference.
If you know the coefficient of friction how do you find the maximum velocity to maintain a circular path at a given radius?
say mass(m) = 10 kg, radius(r) = 10 m, say friction coefficient = 0.5 force to break friction = 10 * 0.5 = 5 kgf = say 50 n to find acceleration required to produce this force use f=m*a, shuffle to a = f / m so a = 50 / 10 = 5 (m/s)/s, install in a = v^2 / r, so 5 = v^2 / 10, so 10 * 5 = v^2, so sq. root 50 = v, so v = 7.07 metres / second if friction coefficient and radius remain the same, altering the mass wont alter the velocity at breakaway point
Does a rollercaoster have greater kinetic energy if it fall from 25 meters instead of 10 meters?
yes as long as friction is negligible.
Does 0.1 mean 10?
No. 10 is 100 times greater than .1
What number is greater 10 to the power 390?
If you mean "greater than", you can raise it to a higher power.
When using scientific notation the the coefficient is less than what?
When using scientific notation, the coefficient must be between greater than or equal to 1, and less than 10. For example, 5.17, 9.63, and 1.49 are all correct coefficients, while 0.12 and 10.87 are not.
A material has a coefficient of volume expansion of 60×10^-6/degree celsius. What is its coefficient of expansion?
120×10^-6
What will be the acceleration of a block of mass 10kg a force of 50Newton is acting on it coefficient of friction is 0.5Newton and the block is at rest initially?
Coefficent of friction isn't measured in Newtons. F=COF.R R=mg therefore F=49.05N F=ma a=(50-49.05)/10 a=0.095m.s-2
What is Q-10?
temperature coefficient =10 degree celsius..
What is a coefficient?
A coefficient is a number in front of a variable (i.e. multiplied by it).For example, in the expression x2 - 10x + 25, the coefficient of x2 is 1 and the coefficient of x is -10. The third term, 25, is a constant.If the expression were -x2 + 10x + 25, the coefficient of x2 would be -1, and the coefficient of x would be 10.
What is the friction force for on a sliding 10kg textbook that has a kinetic friction coefficient of 0.1?
Ff=µFn Ff is force of friction µ is the coefficient of friction Fn is the normal force Normal force is the force that keeps things from going through each other. It is perpendicular to the surface the text book is sitting on, and equal to all forces perpendicular to and pushing against it. Assuming the text book is on a flat, level table on earth, the forces that the Normal force counteracts would be simple: gravity. So Fg=9.8*10 Fn=98 and.. Ff=.1*98 is: 9.8
