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If the gas behaves as a perfect gas, it obeys Boyle's Law, which can be stated as 'at constant temperature, pressure is inversely proportional to volume'. In this case the pressure is multiplied by 5/2, so the volume will be 2/5 of the original, i.e. 2 l.

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Katheryn Barrows

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2y ago
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12y ago

Combined gas law:

P1V1 P2V2

----- = -----

T1 T2

P1= 10.0 ATM

V1= 5.00 L

T1= 500 K

P2= Unknown

V2= 10.0 L

T2= 200 K

10.0 × 5.00 / 500 = P2 × 10.0 / 200

P2= 2.00 ATM

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12y ago

For this you would use Boyle's Law, P1V1 = P2V2. The first pressure and volume variables are before the change, while the second set are after the change. In this case, the volume is being changed and the pressure has to be solved for.

P1 = 1.00 ATM

V1 = 5.00 L

P2 = Unknown

V2 = 2.00 L

P1V1 = P2V2

1.00(5.00)=2.00P

P= 2.5 ATM

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14y ago

That's Boyle's law. If the temperature remains the same then

(P1)(V1) = (P2)(V2)

where

P1 is the old pressure,

V1 is the old volume,

P2 is the new pressure,

V2 is the new volume.

Substituting:

(200)(2500)=(500)(V2)

500000= (500)(V2)

Divididing both sides by 500

1000 = V2

So the new volume of the gas is 1000 cubic meters.

Note: The gas has been compressed tighter, so it takes up

less space or volume.

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10y ago

Boyle's Law applies to this question. It states that at constant temperature, the volume of a gas is inversely proportional to its pressure. In this case, the volume at 2.0 ATM would be 26 liters.

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7y ago

If the gas behaves as a perfect gas, it obeys Boyle's Law, which can be stated as 'at constant temperature, pressure is inversely proportional to volume'. In this case the pressure is multiplied by 5/2, so the volume will be 2/5 of the original, i.e. 2 l.

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14y ago

P1V1=P2V2

P1=2.0 atm

V1=200 mL

V2=10 mL

P2=(P1V1)/V2

P2=(2.0*200)/(10)

P2=40 atm

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13y ago

Use Boyle's Law, P1V1= P2V2

Rearrange for P2: P2=(P1V1)/V2

P2= (5.0x10.0)/2.0

P2= 25 atm

The pressure of the gas after it is compressed is equal to 25 atmospheres.

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14y ago

1,000 cubic meters..

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7y ago

It is reduced to 2 L.

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Q: A gas with pressure of 5.0 ATM is compressed at constant temperature from 10.0 L to 2.0 L. .What is the pressure of the gas after it is compressed?
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