STP = Standard Temperature and Pressure
After the IUPAC rules the standard temperature is 0 0C and the standard pressure is 100 kPa (0,986 atm).
The molar volume of an ideal gas at STP is 22,710 980(38) L.
Vc is the specific volume (volume per mole) at the critical point of a substance. Vr is the "reduced volume" which is equal to the specific volume divided by the critical volume. Vr = V/Vc Many thermodynamic models correlate behavior of different substances in terms of their reduced volume. The principle of corresponding states indicates that substances at equal reduced pressures and temperatures have equal reduced volumes. This relationship is approximately true for many substances, but becomes increasingly inaccurate for large values of Pr. (Where Pr = P/Pc and Pc is the pressure at the critical point.)
Firstly, an ideal gas is one consisting of identical particles with no volume. These particles feel no intermolecular forces and undergo perfectly elastic collisions with the all of the container. It is important to note that real gases do not exhibit these characteristics and that it merely provides an approximation. Though the heading "Ideal Gas" can be separated into two board sections, the classical thermodynamic ideal gas and the ideal quantum Boltzmann gas; from the question wording I'll assume it's the former we're dealing with (both are essentially the same, except that the classical thermodyamic ideal gas is based on classical thermodynamics alone). The classical ideal gas pressure, p, and its volume, V, are related in the following way: pV=nRT where n is the amount of gas in moles , R is the gas constant, 8.314J•K-1mol-1 (Joule Kelvin per mole) and T is the absolute temperature in Kelvin. Put simply : the relationship between pressure and volume is the that the change in pressure is inversly proportional to the volume. p= a/Vwhere a is a constant; in this case (nRT).
Pressure and temperature. As pressure increases, volume decreases; as temperature increases, volume increases with it. At standard temperature and pressure (1 atm, 273 degrees Kelvin), one mole of a gas (6.022 x 1023 particles) has the volume of 22.4 liters.
Pressure and volume are inversely proportional at any given temperature and quantity of molecules. Thus, a mole of gas squeezed into half the volume would have double the pressure if all other things remain equal. Conversely, a mole of gas whose pressure was halved would occupy double the volume, all other things remaining equal.
The ideal gas law is given by PV = nRT, where P is pressure, V is volume, n is moles of gas, R is the gas constant, and T is temperature. Plugging in the values, we get P = (1 mole)(8.314 J/mol*K)(298 K) / 12 L = 2057 Pa or 2.06 kPa.
For Ideal gases, mole fraction=volume fraction
The volume fraction of a substance is equal to the mole fraction for ideal gas mixture
The volume varies inversely with pressure.
The ideal gas constant ( R ) with a value of 0.0821 has units of liters·atmospheres per mole·kelvin (L·atm/(mol·K)). This means it describes how much volume one mole of an ideal gas occupies at standard temperature and pressure. The units reflect the relationship between pressure, volume, temperature, and the amount of substance in the ideal gas law equation, ( PV = nRT ).
Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
The volume is 22,710 980(38) litres for the ideal gas.
This is the molar volume of an ideal gas at a given temperature and pressure.
1 mole of an ideal gas at STP occupies 22.4 liters. If STP is 'close' to the boiling point a real gas may deviate from ideal behavior and thus the volume will not be as predicted.
The volume of a mole of any gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters. This is known as the molar volume of a gas at STP and is a standard value used in gas calculations.
The volume occupied by a mole of an ideal gas can be calculated using the ideal gas law equation: PV = nRT. Convert the pressure to atm (1 atm = 760 mmHg), and the temperature to Kelvin (25.0°C = 298 K). Then substitute the values into the equation and solve for volume (V).
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
At NTP (normal temperature and pressure), 1 mole of any gas occupies approximately 24 liters of volume. This is due to the ideal gas law, which relates the volume, pressure, temperature, and amount of gas.